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garik1379 [7]
3 years ago
15

Which number is equal to 10 Superscript negative 3? –1,000 –30 0.001 0.003

Mathematics
2 answers:
Sever21 [200]3 years ago
7 0

Answer:

The answer is C, 0.001

Step-by-step explanation:

I took the test on ED 2020, and got 100%, so this is 100% correct. Have a wonderful day!!!!!!!!

Karolina [17]3 years ago
5 0

<u>Given</u>:

The given expression is 10^{-3}

We need to determine the equivalent number.

<u>Equivalent expression:</u>

To determine the equivalent number, let us solve the expression 10^{-3}

Thus, let us apply the exponent rule a^{-b}=\frac{1}{a^{b}} , we get;

10^{-3}=\frac{1}{10^{3}}

Also, the term 10³ can be written as 10^{3}=1000

Thus, we get;

\frac{1}{1000}

Dividing, we get;

0.001

Hence, the equivalent number is 0.001

Hence, Option c is the correct answer.

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Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

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  • g(x)=x+5
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  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

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Step-by-step explanation:

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