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Luda [366]
3 years ago
11

1. Let x[n] be a signal with x[n] = 0 for n<-1 and n > 3. For each signal given below, determine the values of n for which

it is guaranteed to be zero. (a) x [n -2] (b) x [n+ 3] (c) x [-n + 1]
Mathematics
1 answer:
valentina_108 [34]3 years ago
4 0

Answer:

a) n<1 and n>5

b)  0 < n < -4

c)  n > 2 and n < -2

Step-by-step explanation:

The signal is given by x[n] = 0 for n < -1 and n > 3

The problem asks us to determine the values of n for which it's guaranteed to be zero.

a) x[n-2]

We know that n -2 must be less than -1 or greater than 3.

Therefore we're going to write down our inequalities and solve for n

n-2

Therefore for n<1 and n>5 x [n-2] will be zero

b) x [n+ 3]

Similarly, n + 3 must be less than -1 or greater than 3

n+30

Therefore for n< -4 and n>0, in other words, for 0 < n < -4  x[n-2] will be zero

c)x [-n + 1]

Similarly, -n+1 must be less than -1 or greater than 3

-n+13-1\\-n>2\\n

Therefore, for n > 2 and n < -2  x[-n+1] will be zero

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