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3 years ago

If the moon is approximately 3.6310/8 meters from earth what is 3.6310/8 in standard Notation

Mathematics

2 answers:

disa [49]3 years ago

8 0

Move the decimal to the right 8 places

Andreyy893 years ago

5 0

Answer:

the write answer is 363,000,000

Step-by-step explanation:

I promise I did it on Ed

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Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea

elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) = P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725

There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

$nCk=\frac{n!}{k!(n-k)!}$

So, the number of ways to select exactly 3 aces is:

$4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192$

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

$P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}$

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

$P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052$

5 0

3 years ago

X(x+3) + 34 = (x +5)(x+2)

My name is Ann [436]

X(x + 3) + 34 = (x + 5)(x + 2)

First, expand to remove parentheses.
$x^{2} + 3x + 34 = x^{2} + 2x + 5x + 10$
Second, add '2x + 5x' to get '7x'.
$x^{2} + 3x + 34 = x^{2} + 7x + 10$
Third, cancel out ' $x^{2}$ ' on both sides.
$3x + 34 = 7x + 10$
Fourth, subtract '3x' from both sides.
$34 = 7x + 10 - 3x$
Fifth, subtract '7x - 3x' to get '4x'.
$34 = 4x + 10$
Sixth, subtract '10' from both sides.
$34 - 10 = 4x$
Seventh, subtract '34 - 10' to get '24'.
$24 = 4x$
Eighth, divide both sides by '4', leaving the 'x' by itself.
$\frac{24}{4} =x$
Ninth, since '24 ÷ 4 = 6', simplify the fraction to '6'.
$6 = x$
Tenth, switch your sides to get the answer.
$x = 6$

Answer: x = 6

4 0

3 years ago

Given RT below, if S lies on RT such that the ratio of RS to ST is 3:1, find the coordinates of S.

Ksivusya [100]

Answer:

S(-2, -3)

Step-by-step explanation:

Find the diagram attached below,=. Frim the diagram, the coordinate of R and T are (-5, 3) and (-1, -5) respectively. If the ratio of RS to ST is 3:1, the coordinate of S can be gotten using the midpoint segment formula as shown;

S(X, Y) = {(ax1+bx2/a+b), (ay1+by1/a+b)} where;

x1 = -5, y1 = 3, x2 = -1, y2 = -5, a = 3 and b =1

Substitute the values into the formula;

X = ax2+bx1/a+b

X = 3(-1)+1(-5)/3+1

X = -3-5/4

X = -8/4

X = -2

Similarly;

Y = ay2+by1/a+b

Y = 3(-5)+1(3)/3+1

Y = -15+3/4