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dolphi86 [110]
3 years ago
7

When solving a system of equations of A and B, we get no solution. When solving B and C, the solution is (0,3). When solving A a

nd D, the solution is the origin. When solving B and D, the solution is (-1.5, 1.5). What is the solution when solving A and C? What are the equations of all lines?
Mathematics
2 answers:
Aliun [14]3 years ago
4 0

Step-by-step explanation:

How do we set about finding the points in which two graphs y = f(x) and y = g(x) intersect?

We already know how to find where the graph of f(x) cuts the x−axis. That’s where y = 0. We calculate it by solving the equation  f(x) = 0 .

When the graphs of y = f(x) and  y = g(x)  intersect , both graphs have exactly the same x and y values. So we can find the point or points of intersection by solving the equation  f(x) = g(x). The solution of this equation will give us the x value(s) of the point(s) of intersection. We can then find the y value by putting the value for x that we have found into one of the original equations. That is by calculating either f(x) or g(x).

Example 1 

Calculate the point of intersection of the two lines f(x) = 2x − 1 and g(x) = x + 1.  First let’s look at a graph of the two functions. We can see the point of intersection is (2, 3).



We calculate the point of intersection by solving the equation f(x) = g(x). That is:

    2x − 1 = x + 1

    2x − x = 1 + 1

            x = 2

The y coordinate can now be found by calculating f(2):

    f(2) = 2×2 − 1 = 3

The point of intersection is (2, 3).

The example shows that we can find the point of intersection in two ways.

Either graphically, by drawing the two graphs in the same coordinate system, or algebraically by solving the equation such as the one in the above example.

Solving an equation graphically is easy with a graphical calculator or a computer program such as Excel.

Some equations cannot be solved algebraically but we can find solutions that are correct to as many significant figures as we want by using computers and calculators

a_sh-v [17]3 years ago
3 0
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It would be 30 degrees since a line is 180. You subtract 150 from 180 and get 30.
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3 years ago
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Eric has $25 to purchase magazines and to pay for his lunch. Each
faust18 [17]

Answer:

B

Step-by-step explanation:

The maximum amount Eric can spend on magazines is $25 less the cost of lunch, $15.

The appropriate inequality sign would be less than since he cannot spend more than $25.

Also, the amount he can spend on magazines would be what is left after paying for lunch.

So the correct inequality is 4m - 15 < 25

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3 years ago
How many squares are in this figure in all?
Tanya [424]

Answer:

explanation

Step-by-step explanation:

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3 years ago
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John, Joe, and James go fishing. At the end of the day, John comes to collect his third of the fish. However, there is one too m
Dmitry [639]

Answer:

The minimum possible initial amount of fish:52

Step-by-step explanation:

Let's start by saying that

x = is the initial number of fishes

John:

When John arrives:

  • he throws away one fish from the bunch

x-1

  • divides the remaining fish into three.

\dfrac{x-1}{3} + \dfrac{x-1}{3} + \dfrac{x-1}{3}

  • takes a third for himself.

\dfrac{x-1}{3} + \dfrac{x-1}{3}

the remaining fish are expressed by the above expression. Let's call it John

\text{John}=\dfrac{x-1}{3} + \dfrac{x-1}{3}

and simplify it!

\text{John}=\dfrac{2x}{3} - \dfrac{2}{3}

When Joe arrives:

  • he throws away one fish from the remaining bunch

\text{John} -1

  • divides the remaining fish into three

\dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3}

  • takes a third for himself.

\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}

the remaining fish are expressed by the above expression. Let's call it Joe

\text{Joe}=\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}

and simiplify it

\text{Joe}=\dfrac{2}{3}(\text{John}-1)

since we've already expressed John in terms of x, we express the above expression in terms of x as well.

\text{Joe}=\dfrac{2}{3}\left(\dfrac{2x}{3} - \dfrac{2}{3}-1\right)

\text{Joe}=\dfrac{4x}{9} - \dfrac{10}{9}

When James arrives:

We're gonna do this one quickly, since its the same process all over again

\text{James}=\dfrac{\text{Joe} -1}{3}+ \dfrac{\text{Joe} -1}{3}

\text{James}=\dfrac{2}{3}\left(\dfrac{4x}{9} - \dfrac{10}{9}-1\right)

\text{James}=\dfrac{8x}{27} - \dfrac{38}{27}

This is the last remaining pile of fish.

We know that no fish was divided, so the remaining number cannot be a decimal number. <u>We also know that this last pile was a multiple of 3 before a third was taken away by James</u>.

Whatever the last remaining pile was (let's say n), a third is taken away by James. the remaining bunch would be \frac{n}{3}+\frac{n}{3}

hence we've expressed the last pile in terms of n as well.  Since the above 'James' equation and this 'n' equation represent the same thing, we can equate them:

\dfrac{n}{3}+\dfrac{n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}

\dfrac{2n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}

L.H.S must be a Whole Number value and this can be found through trial and error. (Just check at which value of n does 2n/3 give a non-decimal value) (We've also established from before that n is a multiple a of 3, so only use values that are in the table of 3, e.g 3,6,9,12,..

at n = 21, we'll see that 2n/3 is a whole number = 14. (and since this is the value of n to give a whole number answer of 2n/3 we can safely say this is the least possible amount remaining in the pile)

14=\dfrac{8x}{27} - \dfrac{38}{27}

by solving this equation we'll have the value of x, which as we established at the start is the number of initial amount of fish!

14=\dfrac{8x}{27} - \dfrac{38}{27}

x=52

This is minimum possible amount of fish before John threw out the first fish

8 0
3 years ago
Mr.Davis drives 496 miles in eight hours. At this rate, how many miles does he drive in six hours?
Lynna [10]

Answer:

Step-by-step explanation:

496m=8h

Figure for 1 hour.

496/8=62

Now do

62x6=372m

Yes, you are correct.

3 0
3 years ago
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