R in this equation refers to the radius
A right triangle's longest side is the hypotenuse
let x=longest, y=middle, and z=shortest
x=y+2
y=2z-1
therefore x=(2z-1)+2=2z+1
find z
z^2+y^2=x^2 by Pythagorean theorem
plug in x and y in terms of z
z^2+(2z-1)^2=(2z+1)^2
z^2+4z^2-4z+1=4z^2+4z+1
subtract the right-hand side's value from the left-hand side's
z^2-8z=0
z(z-8)=0
z=0, 8
z cannot be zero as the sides must have some value to it.
Therefore the shortest side is equal to 8
Answer:
1. Evaluate 3y - 4 for y =5
3*(5)-4=15-4=11
2. 65 + x = 99 x = ?
65+x=99
x=99-65
x=34
3. Find the product. 38.7 *21
38.7*21=812.7
4. Which value satisfies the equation? 9x + 3 = 30
The right value for x would be:
9x+3=30
9x=30-3
9x=27
x=27/9=3
Step-by-step explanation:
Answer:
2/12
Step-by-step explanation:
Because there are 6 tile total but he wants two put 2 numbers out of the bag twice..... you get the 12 because he pulls a number out twice and since he has 6 and then does it again it adds to 12 so the answer would be 2/12
