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WARRIOR [948]
3 years ago
8

Can someone help me with my latest question

Mathematics
2 answers:
Artyom0805 [142]3 years ago
6 0

Answer:

yea

Step-by-step explanation:

Gelneren [198K]3 years ago
5 0

Answer:

Hey!

I understand you want help, but there are tons and tons of users on Brainly. Whether they come for help or <em>to </em>help, there are a lot. Like a lot! So there are so many questions to answer.

So if you're latest question doesn't get answered, whether it be difficulty or time, it probably just means that someone didn't quite get to it.

Also, yes, I will look at it!

Thank you!

Sahkfam

You might be interested in
Find the cube roots of 27(cos 330° + i sin 330°)
Aleksandr-060686 [28]

Answer:

See below for all the cube roots

Step-by-step explanation:

<u>DeMoivre's Theorem</u>

Let z=r(cos\theta+isin\theta) be a complex number in polar form, where n is an integer and n\geq1. If z^n=r^n(cos\theta+isin\theta)^n, then z^n=r^n(cos(n\theta)+isin(n\theta)).

<u>Nth Root of a Complex Number</u>

If n is any positive integer, the nth roots of z=rcis\theta are given by \sqrt[n]{rcis\theta}=(rcis\theta)^{\frac{1}{n}} where the nth roots are found with the formulas:

  • \sqrt[n]{r}\biggr[cis(\frac{\theta+360^\circ k}{n})\biggr] for degrees (the one applicable to this problem)
  • \sqrt[n]{r}\biggr[cis(\frac{\theta+2\pi k}{n})\biggr] for radians

for  k=0,1,2,...\:,n-1

<u>Calculation</u>

<u />z=27(cos330^\circ+isin330^\circ)\\\\\sqrt[3]{z} =\sqrt[3]{27(cos330^\circ+isin330^\circ)}\\\\z^{\frac{1}{3}} =(27(cos330^\circ+isin330^\circ))^{\frac{1}{3}}\\\\z^{\frac{1}{3}} =27^{\frac{1}{3}}(cos(\frac{1}{3}\cdot330^\circ)+isin(\frac{1}{3}\cdot330^\circ))\\\\z^{\frac{1}{3}} =3(cos110^\circ+isin110^\circ)

<u>First cube root where k=2</u>

<u />\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(2)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ+720^\circ}{3})\biggr]\\3\biggr[cis(\frac{1050^\circ}{3})\biggr]\\3\biggr[cis(350^\circ)\biggr]\\3\biggr[cos(350^\circ)+isin(350^\circ)\biggr]

<u>Second cube root where k=1</u>

\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(1)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ+360^\circ}{3})\biggr]\\3\biggr[cis(\frac{690^\circ}{3})\biggr]\\3\biggr[cis(230^\circ)\biggr]\\3\biggr[cos(230^\circ)+isin(230^\circ)\biggr]

<u>Third cube root where k=0</u>

<u />\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(0)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ}{3})\biggr]\\3\biggr[cis(110^\circ)\biggr]\\3\biggr[cos(110^\circ)+isin(110^\circ)\biggr]

4 0
3 years ago
.75x-20= 620 what does x equal rounded to the nearest 100?
vodomira [7]

To solve this, we’ll have to use inverse operations.

Since addition is the inverse to subtraction, we’ll add 20 to 620.

20 + 620 = 640

From there, since division is the inverse of multiplication, we’ll divide .75 by 640.

640/.75 = 853.33333 repeating. We can round this to 853.33, to round to the nearest hundredth.

Therefore, 853.33 would be your answer! You can check this by solving the equation forwards (853.33 x .75 = ~640, 640 - 20 = 620.)

Hope this helps! :)

4 0
3 years ago
The cost of 4 cartons of fresh cream is $7.96. What is the cost of 14 cartons WHOEVER ANSWERS FIRST IS BRAINLIEST​
podryga [215]

Answer:1.99*14= 27.86 Monies

Step-by-step explanation:

3 0
2 years ago
What is 19/20 as a terminating decimal
natka813 [3]
\frac{19}{20} = 0.95
3 0
3 years ago
Read 2 more answers
Write an equation of the line that passes through (5, −1) and is perpendicular to the line y=12x−1.
Lisa [10]

Step-by-step explanation:

solution

let,A(5,-1)

given

y=12x-1

or, y = 12 × x + (-1)

comparing it with y=mx+c

we get

x=1

y = c = -1

now

A(5,-1) and B(1,-1)

equation of line is,

(y-y1)/(x-x1) = (y2-y1)/(x2-x1)

or, (y+1)/(x-5) = (-1+1)/(1-5)

or, (y+1)/(x-5) = 0/-4

cross multiply

-4y-4 = 0

or, 0=4y+4

or, 4y+4=0 is the required eqn

I think this is the process and answer too.

I hope this helps you

4 0
3 years ago
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