Question

Solve for y. ln(y-1)-ln2=x+ln x

Answer 1

$ln(y - 1) - ln(2) = x + ln(x)$
$e^{ln(y - 1) - ln(2)} = e^{x + ln(x)}$
$\frac{e^{ln(y - 1)}}{e^{ln(2)}} = e^{x} * e^{ln(x)}$
$\frac{y - 1}{2} = e^{x} * x$
$\frac{1}{2}y - \frac{1}{2} = xe^{x}$
$2(\frac{1}{2}y - \frac{1}{2}) = 2xe^{x}$
$y - 1 = 2xe^{x}$
$y = 2xe^{x} + 1$