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Ugo [173]
4 years ago
14

8x - 6(x + 1) < 4(2x - 9)

Mathematics
1 answer:
Effectus [21]4 years ago
6 0

Answer:

x > 5

Step-by-step explanation:

Order of Operations: BPEMDAS

Step 1: Write out equation

8x - 6(x + 1) < 4(2x - 9)

Step 2: Distribute parenthesis

8x - 6x - 6 < 8x - 36

Step 3: Combine like terms

2x - 6 < 8x - 36

Step 4: Subtract 2x on both sides

-6 < 6x - 36

Step 5: Add 36 on both sides

30 < 6x

Step 6: Divide both sides by 6

5 < x

Step 7: Rewrite

x > 5

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Answer:

V=1.3(repeating)A+1.3(repeating)M

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3 years ago
A card game has 50 cards. After dealing 7 cards to each player, tupi has 15 cards left over. solve the equation
KIM [24]
50 - 15 = 35

35 ÷ 7 = 5

So there were 5 players and your equation would be:-

50 - 15 ÷ x = 5

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Hope i helped:P  
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3 years ago
What is the area of a rectangle if 1 base is 14 in, the 2nd base is 3.5 in and the height is 8 in?​
algol13

Check the picture below.

notice, we have three pair of sides, let's add them all up to get the area

\stackrel{\textit{left and right}}{2(8\cdot 14)}+\stackrel{\textit{front and back}}{2(3.5\cdot 8)}+\stackrel{\textit{top and bottom}}{2(3.5\cdot 14)}\implies 378~in^2

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3 years ago
Writing an inequality for x that would give this rectangle a perimeter of at least 300 ft.
sdas [7]
This is how I did it, I really hope it helped you with your homework

4 0
3 years ago
Read 2 more answers
Find the coordinates of the other endpoint of the​ segment, given its midpoint and one endpoint.​ (Hint: Let​ (x,y) be the unkno
makkiz [27]

Step-by-step explanation:

Hey, there!!

Here, one point is A(10,8) and P(8,5) is the midpoint.

Let B(x,y) be the another end point.

Now,

Using midpoint formulae,

p(x.y) =  \frac{x1 + x2}{2} . \frac{y1 + y2}{2}

p(8.5) = ( \frac{10 + x}{2} . \frac{8 + y}{2} )

Since they are equal,equating with their corresponding elements we get,

8 =  \frac{10 + x}{2}

or, 16 = 10 + x

or, x=16-10

Therefore, x = 6

Now,

5 =  \frac{8 + y}{2}

or, 10 = 8 + y

or, y = 2

Therefore, The coordinates of another point are B(6,2)

<em><u>Hope it helps</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

8 0
4 years ago
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