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Fantom [35]
3 years ago
11

Label the points, lines, and planes to show AB and line m perpendicular to each other in plane S at point B. plane S

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0

Answer:

Please fins attached the required labelled drawing

Step-by-step explanation:

The given parameters are;

1) Lines AB and m are both coplanar on plane S and are perpendicular to each other intersecting at point B

2) Plane R and plane S intersect on line p

3) Line AB and line p are perpendicular to each other and both intersect with line n at point A

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8/x = 32 <br> ..................
krok68 [10]

Answer:

Step-by-step explanation:

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6 0
2 years ago
Find x<br><br><br><br><br> Thanks for the help in advance!
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I'm not sure if this is the easiest way of doing this, but it surely work.

Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

AH=2,\quad HB=6,\quad AC=x

Moreover, let CH=y and BC=z

Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

\begin{cases}4+y^2=x^2\\36+y^2=z^2\\x^2+z^2=64\end{cases}

If we solve the first two equations for y squared, we have

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