What is the point-slopw form of the line that passes through the given point and has the given slop?

Mathematics

1 answer:

AlladinOne [14]3 years ago

7 0

Point slope form is $y - y_1 = m(x-x_1)$ in general where

m = slope
(x1,y1) = point the line goes through

In this case, m = 5 is the given slope

(x1,y1) = (1,3) is the given point the line goes through which means
x1 = 1
y1 = 3

So let's plug m = 5, x1 = 1, y1 = 3 into the general equation above to get...

$y - y_1 = m(x-x_1)$

$y - 3 = 5(x-1)$

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So the final answer is $y - 3 = 5(x-1)$

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What kind of sequence is the pattern 1, 6, 7, 13, 20, ...?

AlexFokin [52]

Answer:

The given sequence 6, 7, 13, 20, ... is a recursive sequence

Step-by-step explanation:

As the given sequence is

$6, 7, 13, 20, ...$

It cannot be an arithmetic sequence as the common difference between two consecutive terms in not constant.

$d = 7-6=1$ , $d = 13-7=6$

As d is not same. Hence, it cannot be an arithmetic sequence.

It also cannot be a geometrical sequence and exponential sequence.

It cannot be geometric sequence as the common ratio between two consecutive terms in not constant.

$r = 7-6=1$ , $r = 13-7=6$

$r = \frac{7}{6}$ , $r = \frac{13}{7}$

As r is not same, Hence, it cannot be a geometric sequence or exponential sequence. As exponential sequence and geometric sequence are basically the same thing.

So, if we carefully observe, we can determine that: