Answer:
In order to have ran 33 miles, Bobby would have to attend <em>32 track practices.</em>
Step-by-step explanation:
Solving this problem entails of uncovering the amount of track practices Bobby must attend in order to have ran 33 miles. Start by reading the problem carefully to break down the information provided.
You can see that Bobby has already ran one mile on his own. This is important to remember for later. The problem also states that he expects to run one mile at every track practice.
Setting up an equation will help us solve. Here is how we could set up the equation:
(<em>amount of miles already ran</em> = 1) + (<em>number of track practices</em> = x) = (<em>total miles to run</em> = 33)
1 + x = 33
The equation is now in place. You can solve this, or isolate <em>'x',</em> by using the subtraction property of equality. This means we will subtract one from both sides of the equation, thus isolating the variable.
1 + x = 33
1 - 1 + x = 33 - 1
x = 32
The variable is the only term left on the left side of the equation. This means Bobby must attend track practice <em>32 times</em> in order to have ran 33 miles.
See the attached picture:
Part b to 4 decimal places would be 0.6630
Answer:
y=-2x+16
Step-by-step explanation:
since you are given the slope, you can plug it into the equation y=mx+b where m= slope and b= y intercept
you now have y=-2x+b
to find b, you have to plug in the coordinate you are given into the equation
6=-2(5)+b and solve for b
6=-10+b
b=16
since you now have both the slope & y intercept, you can plug them both back into the original equation, y=mx+b and you get
y=-2x+16
if you have any questions, feel free to ask :)
Answer:
One way between subjects ANOVA
Step-by-step explanation:
In the between groups ANOVA, different people tests each conditions corresponding to the variables in the study while for the within groups ANOVA, the same person tests for all conditions corresponding to the variables. This way the total number of participants will be larger in the between subjects ANOVA group.