1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
Answer:
Volume of cone = 418.67 cm³ (Approx.)
Step-by-step explanation:
Given:
Radius of cone = 5 cm
Height of cone = 16 cm
Find:
Volume of cone
Computation:
Volume of cone = [1/3][π][r²][h]
Volume of cone = [1/3][3.14][5²][16]
Volume of cone = [1/3][3.14][25][16]
Volume of cone = [1/3][3.14][400]
Volume of cone = [1/3][1,256]
Volume of cone = 418.67 cm³ (Approx.)
Answer:
6th floor
Step-by-step explanation:
2-3+7
-1+7
6
Answer:
h= 4.6, c=7.1
Step-by-step explanation:
First you need to know in a 30 60 90 triangle the sides ratios are x, 2x and x√3, and for 45 90 45 it is x, x and x√2
so <em>h</em> is 8/√3 and you rationalize the bottom so it becomes 8√3/3. when you solve this and round to nearest hundred it becomes 4.6. for the second one, it is 5√2 and when you solve this and round, it becomes 7.1
