1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm² 9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length area of the section=side²=(40 cm)²=1600 cm² 1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m² Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar: volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data: density=8.10³ kg/m³ volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
It’s letter D. “Litotes is a figure of speech and a form of understatement in which a sentiment is expressed ironically by negating its contrary.” Hope this helps
