The answer is -5 hope this works
1. 5m+3n=41
3m-6n=9 (multiplying the first equation by 3 and the second by 5), we get;
15m+9n=123
15m-30n= 45 (subtracting the two equations)
39n = 78
n = 2, and
to get m we substitute n with 2
3m = 9+6(2)
3m = 21
m = 7
Therefore, n=2 and m=7
2. 6g +8h=40
-6g +2h = -20(Adding the two equations to eliminate g)
10 h= 20
h =2
to get g we substitute h with two
6g= 40- 8(2)
= 24
g= 4
Therefore, g =4 and h =2
3. 9x +5y =35
2x + 5y =0 (subtracting the two equations to eliminate y)
7x =35
x= 5
To get y we substitute x with 5
5y=35-9(5)
5y = -10
y = -2
Therefore, x=5 and y=-2
Area of square is A1
A1=a^2
a=2m
A1=2^2
A1=4 m^2
Area of equilateral triangle is A2
A2=h•b/2
b=2 m
h= √3/2 •b
h= √3•2/2
h= √3
A2= √3 •2/2
A2= √3
Area of a shape A
A=A1-A2
A=4-√3
A=4-1.73
A=2.27 m^2
Answer:
If you asking whats in the hundredths place it's 0. so you would say it as four-hundred one and 30 hundredths.
But your answer should be 0 hundredths.
