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3 years ago

At Target you can buy 45 oz. of Sprite for

2 answers:

5 0

Walmart is better because you get 20 oz extra for 4 cents cheaper than target which gives you less oz for almost the same price

Sophie [7]3 years ago

4 0

Answer:

walmart

Step-by-step explanation:

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What is the slope formula?

Ksivusya [100]

Answer:

Step-by-step explanation:

3 0

3 years ago

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given examples of relations that have the following properties 1) relexive in some set A and symmetric but not transitive 2) equ

rodikova [14]

Answer: 1) R = {(a, a), (а,b), (b, a), (b, b), (с, с), (b, с), (с, b)}.

It is clearly not transitive since (a, b) ∈ R and (b, c) ∈ R whilst (a, c) ¢ R. On the other hand, it is reflexive since (x, x) ∈ R for all cases of x: x = a, x = b, and x = c. Likewise, it is symmetric since (а, b) ∈ R and (b, а) ∈ R and (b, с) ∈ R and (c, b) ∈ R.

2) Let S=Z and define R = {(x,y) |x and y have the same parity}

i.e., x and y are either both even or both odd.

The parity relation is an equivalence relation.

a. For any x ∈ Z, x has the same parity as itself, so (x,x) ∈ R.

b. If (x,y) ∈ R, x and y have the same parity, so (y,x) ∈ R.

c. If (x.y) ∈ R, and (y,z) ∈ R, then x and z have the same parity as y, so they have the same parity as each other (if y is odd, both x and z are odd; if y is even, both x and z are even), thus (x,z)∈ R.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial but not transitive, so the relation provided in (1) satisfies this condition.

Step-by-step explanation:

1) By definition,

a) R, a relation in a set X, is reflexive if and only if ∀x∈X, xRx ---> xRx.

That is, x works at the same place of x.

b) R is symmetric if and only if ∀x,y ∈ X, xRy ---> yRx

That is if x works at the same place y, then y works at the same place for x.

c) R is transitive if and only if ∀x,y,z ∈ X, xRy∧yRz ---> xRz

That is, if x works at the same place for y and y works at the same place for z, then x works at the same place for z.

2) An equivalence relation on a set S, is a relation on S which is reflexive, symmetric and transitive.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial and not transitive.

QED!

6 0

3 years ago

Is 1/4 of 200 greater than 1/2 of 100

MAVERICK [17]

No beacuse 1/4 would be less that 1/2 it's common sense

6 0

3 years ago

Sabiendo que el segmento DE es paralelo a la base del triángulo, las medidas de los segmentos a y b son...

AleksandrR [38]

Answer:

Para resolver correctamente el ejercicio debemos seguir los pasos que se muestran en la explicación.

Step-by-step explanation:

El ejercicio enunciado de manera completa es el siguiente:

7.Sabiendo que el segmento DE es paralelo a la base del triángulo, las medidas de los segmentos a y b son:

(la gráfica del ejercicio se guardo como archivo adjunto)

-a = 8 cm y b = 10

-a = 9 cm y b = 11

-Ninguna de las respuestas anteriores es correcta.

<em>SOLUCIÓN:</em>

<em>Pasos:</em>

-Primero debemos hallar el valor de a, la gráfica nos indica que debemos hacer,tenemos que restar 15 de 6; entonces:

a= 15cm -6cm=9 cm

-Ahora debemos aplicar el teorema de thales ;como los segmentos son proporcionales podemos establecer la siguiente relación de esa manera podemos hallar el valor del segmento b;

$\frac{9}{b}$ = $\frac{6}{7}$ ( para resolver debemos multiplicar en cruz)

(9x7)=6xb

63=6b (aquí debemos hallar el valor de b,para eso b pasa a dividir a 63)

$\frac{63}{6}$ = b

b= 10.5 cm

La respuesta correcta es: a= 9cm y b= 10.5 cm

(De las opciones de respuesta dadas en el ejercicio ,ninguna corresponde a la respuesta hallada)

8 0

3 years ago

Movies are on sale for 3/4 the original price. If the original price is $10, what is the sale price?

baherus [9]

$\frac{3}{4}\ of\ the\ original\ price=\frac{3}{4}\times\$10=\left(\frac{3}{4}\times\frac{10}{1}\right)\$=\frac{3\times10}{4\times1}\$\\\\=\frac{30}{4}\$=\frac{28+2}{4}\$=\boxed{\boxed{7\frac{2}{4}\$=7\frac{1}{2}\$=\boxed{\$7.50}}}$

4 0

3 years ago

Read 2 more answers