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Crank
3 years ago
13

PLEASE ANSWER QUICK

Mathematics
1 answer:
makvit [3.9K]3 years ago
3 0
For the first equation, I put it in y=mx+b form, so y=-3x-9
the second one is x=4
hope i helped 
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The first time that Arnold ran for mayor in a small town, he received 5% of the votes. This year, when Arnold ran for mayor agai
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Answer:

20 votes

Step-by-step explanation:

You start with the percents: You always start with 100%

100-5=95

Then you multiply

95 x 4

4 is how many votes he received the 2nd time

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Your Welcome :)

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4 years ago
Read 2 more answers
Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t &gt; 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
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