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3 years ago

Solve the system of equations using elimination.

Mathematics

1 answer:

tester [92]3 years ago

8 0

Answer:

y = 16 + 3/11

x = -76/11

Step-by-step explanation:

2y - 5x = -2

3y + 2x = 35

__________

(2y - 5x = -2)*3

(3y + 2x = 35)*2

__________

6y - 15x = -6

6y +4x = 70

__________

(6y - 15x = -6) - (6y +4x = 70)

15x - 4x = -6 -70

__________

11x = -76

x = -76/11

__________

3y +2(-76/11) = 35

3y = 35 + 152/11

3y = 13 + 35 + 9/11

3y = 48 + 9/ 11

y = 16 + 3/11

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Answer:

The answer is x=9 so, its option 3.

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The mother's age is 8 times her son's age. After 6 years, the age of the mother will be 9/2 times her son's age. The present age

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Answer:

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Step-by-step explanation:

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Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).

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<h3>Conner work is correct. Jana work is wrong</h3>

Solution:

Given that,

Conner and Jana are multiplying:

$(3^56^8)(3^96^{10})$

Given Conner's work is:

$(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}$

We have to check if this work is correct

Yes, Conner work is correct

From given,

$(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}$

Use the following law of exponent

$a^m \times a^n = a^{m+n}$

Therefore,

$3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}$

Given Jana's work is:

$(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}$

This is incorrect

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3 years ago

A bakery wants to determine how many trays of doughnuts it should prepare each day. Demand is normal with a mean of 5 trays and

Alexeev081 [22]

Answer:

4 trays should he prepared, if the owner wants a service level of at least 95%.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5

Standard Deviation, σ = 1

We are given that the distribution of demand score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(X > x) = 0.95

We have to find the value of x such that the probability is 0.95

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 5}{1})=0.95$

$= 1 -P( z \leq \displaystyle\frac{x - 5}{1})=0.95$

$=P( z \leq \displaystyle\frac{x - 5}{1})=0.05$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 5}{1} = -1.645\\x = 3.355 \approx 4$

Hence, 4 trays should he prepared, if the owner wants a service level of at least 95%.

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3 years ago