Graph each question y =2x + 0.5

WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!<br> WHAT IS THE AMPLITUDE OF THIS FUNCTION

nika2105 [10]

<em>your answer should be three.</em>

<em />

<em />

4 0

3 years ago

Determine the principal value of the function: Arc sin(square root of 3/2)

Drupady [299]

Answer:

π/3

Step-by-step explanation:

We have to find the principal value of $\text{arc sin}(\frac{\sqrt{3}}{2} )$

arc sin means sin inverse. The sin inverse is a one to one function with its range between $-\frac{\pi}{2} \textrm{ to } \frac{\pi}{2}$

The principal value of the arc sin will lie within the above given range.

value of sin (60) or sin( $\frac{\pi}{3}$ ) is $\frac{\sqrt{3}}{2}$ .

$\frac{\pi}{3}$ lies between $-\frac{\pi}{2}\textrm{ and } \frac{\pi}{2}$

So, from here we can say that the Principal Value of Arc sin(square root of 3/2) is π/3

5 0

3 years ago

Show all work to identify the asymptotes and state the end behavior of the function f(x)=3x/x-9

lorasvet [3.4K]

Using the asymptote concept, we have that:

The vertical asymptote is x = 9.

The horizontal asymptote is y = 3.

The end behavior is that as $x \rightarrow \infty, y \rightarrow 3$ .

<h3>What are the asymptotes of a function f(x)?</h3>

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

$f(x) = \frac{3x}{x - 9}$

For the vertical asymptote, we have that:

x - 9 = 0 -> x = 9.

For the horizontal asymptote:

$y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{3x}{x - 9} = \lim_{x \rightarrow \infty} \frac{3x}{x} = \lim_{x \rightarrow \infty} 3 = 3$

Hence, the end behavior is that as $x \rightarrow \infty, y \rightarrow 3$ .

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

8 0

1 year ago

What is the value of x? O 13 O 14 O 26 O 28

BartSMP [9]

It’s A. 13

hope this helps

7 0

2 years ago

The sum of three numbers is 104. The first number is 10 less than the second. The third number is 4 times the second. What are t

Shalnov [3]

Answer:

The numbers are 9, 19 and 76.

Step-by-step explanation:

Let's take the second number and make it a variable, like x. Now let's find all the other numbers in terms of x.

The first number in terms of x:

$x - 10$

The second number in terms of x:

$4x$

If we add them all up, these 3 numbers in terms of x must be equal to 104, so:

$x + (x - 10) + (4x) = 104 \\ x + x - 10 + 4x = 104 \\ 6x - 10 = 104 \\ 6x = 114 \\ x = 19$

Now that we know the second number, we can find the other numbers since we already figured out their values in terms of x:

$19 - 10 = 9$

$4 \times 19 = 76$

The first number is 9, second number 19 and the third number 76.

6 0

3 years ago