<span>Event A is more likely...Pr(A)=(16/52)(15/51)(14/50)(13/49) .... and Pr(B)= (4/52)(3/51)(2/50)(1/49)</span>
Answer:
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
Of the 2809 people who responded to survey, 1634 stated that they currently use social media.
This means that 
98% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
60 because all the negatives would cancel out so all you have to do is multiply the numbers
7x+1y = 17.00 can be simplified to y = -7x +17
<span>-7x +17 can then be substituted for y in 3x+ 4y =17.50
</span>3x+4(y) = 17.50
3x+ 4(-7x +17) = 17.50
From here you can solve for X
<span>3x + 4(-7x +17) = 17.50
</span>3x -28x + 68 = 17.50
-25x + 68 = 17.50
-68 -68
-25x = -50.50
÷-25 ÷-25
X = 2.02
You can then replace x with 2.02 in the original 7x + 1y = 17.00 to solve for y.
7(x) + 1y = 17.00
7(2.02) + y = 17.00
14.14 + y = 17.00
-14.14 -14.14
y = 2.86
Then substitute 2.02 for x and 2.86 for y in the original 3x+ 4y = 17.50 to check.
3(x) + 4(y) = 17.50
3(2.02) + 4(2.86) = 17.50
6.06 + 11.44 = 17.50
17.50 = 17.50
So
X = 2.02
and
Y = 2.86
or the solution set is (2.02, 2.86)
Hope this helps
