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2 years ago

Solve the equation 42x + 7 = 16

Mathematics

2 answers:

ehidna [41]2 years ago

7 0

Answer:

should get 0.2 hope this helps you!

Step-by-step explanation:

irakobra [83]2 years ago

7 0

Answer: .2

Explanation what i got from my math

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I will give brainliest 35 points The following graph represents the correlation between shoe size and height for 70 people.

Svetllana [295]

Answer:

Positive

Step-by-step explanation:

As height is increasing, shoe size is also increasing (positive slope)

Negative correlation is when one variable increases and the other decreases (negative slope)

5 0

3 years ago

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When (3,-2) is reflected across the x-axis the resulting image point is:

FromTheMoon [43]

Answer:

(3,2)

Step-by-step explanation:

when reflecting across the x axis the y value becomes - while the x value stays the same

4 0

2 years ago

Solve. 1/2x + 3 < 4x - 7 A) x > 8/7 B) x < -8/7 C) x > 20/7

anyanavicka [17]

C would be your answer and here is how you would solve the problem.

5 0

2 years ago

HELP PLZ WILL GIVE YOU BRAINIEST

slamgirl [31]

Answer:

diameter is 16.60 ft

the circumference is 52.12ft

Step-by-step explanation:

Hope this helps!

8 0

3 years ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

3 years ago