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DiKsa [7]
3 years ago
13

A family has two cars. The first car has a fuel efficiency of 30 miles per gallon of gas and the second has a fuel efficiency of

40 miles per gallon of gas. During one particular week, the two cars went a combined total of 1800 miles, for a total gas consumption of 50 gallons. How many gallons were consumed by each of the two cars that week?
Mathematics
2 answers:
Anarel [89]3 years ago
8 0
30x+40(50-x)=1800
Solve for x
X=20 for the first car

50-20=30 for the second car
Ugo [173]3 years ago
6 0
One car 40 miles /gallon
other car 30 miles/gallon
..
Total miles = 165
gas used = 45 gallons
...
let first car drive x miles
second car drive y miles
..
x/40 + y/30 = 45
(30x+40y)/30*40 = 45
30x+40y = 45*40*30
30x+40y=54,000
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5 0
3 years ago
A. Steven wrote an expression with 2 terms. The second term, which is the whole number 7, is subtracted from the first term. The
bulgar [2K]

Answer:

Part a)

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Step-by-step explanation:

Part a)

Let

n-----> the first term

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(n-7)

n=2(2x+5)^{2}

substitute

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2(2x+5)^{2}-7

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Part b)

Let

n-----> the first term

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(3x^{2})+(25x)

Evaluate for x=2

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4 0
3 years ago
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