Answer:
1,686,000
Step-by-step explanation:
Answer:
a. [-3, 4]
b. (-inf, -3]
c. [4, inf)
Step-by-step explanation:
Our intervals will represent the x-values
We know that since there's an arrow pointing to the left of the line that it goes on infinitely
Same thing when the arrow is going to the right
Then we can just looking at the x-values on the graph for the intervals where it starts and stops
Hope this helps
Best of luck
Answer:
There are 12 students in each group
Step-by-step explanation:
87-39= 48
48/4= 12
Hope this helped. ;)
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
