Answer:
16,000 people
Step-by-step explanation:
Let's write a ratio
8,000:20,000
Let's write another ratio
x:40,000
We can write a percent proportion.
We can see that the relationship between the denominators is multiplied by 2 so that means the relationship between 8,000 and x is x is 2 times greater than 8,000
Let me know if you have any questions.
Hi!
I have attached 2 images that should help you understand :)
First, look at the edits I made to the image you posted. I separated the shape into smaller shapes so that we can find the area of each individual one.
Let's start with the rectangle.
To find the area of a rectangle, multiply the width times the height.
10
· 4 = 40
Rectangle = 40cm
Next up, the red triangles.
I have included another image showing the triangles combined into rectangles. So we can find the area of the triangles just like we would rectangles!
(let me know if you don't understand how I found the width + height of the triangles)
5 · 10 = 50
Red triangles = 50cm
And finally, the green triangles.
8 · 7 = 56
Green triangles = 56cm
Add it all together and you get...
40 + 50 + 56 = 146
The answer to the question is
146cm.
Next time you are having trouble with something like this, picture the triangles as rectangles! :)
Answer:
The answer is below
Step-by-step explanation:
Let S denote syntax errors and L denote logic errors.
Given that P(S) = 36% = 0.36, P(L) = 47% = 0.47, P(S ∪ L) = 56% = 0.56
a) The probability a program contains both error types = P(S ∩ L)
The probability that the programs contains only syntax error = P(S ∩ L') = P(S ∪ L) - P(L) = 56% - 47% = 9%
The probability that the programs contains only logic error = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
P(S ∩ L) = P(S ∪ L) - [P(S ∩ L') + P(S' ∩ L)] =56% - (9% + 20%) = 56% - 29% = 27%
b) Probability a program contains neither error type= P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
c) The probability a program has logic errors, but not syntax errors = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
d) The probability a program either has no syntax errors or has no logic errors = P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
