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3 years ago

How do I solve this problem?

Mathematics

2 answers:

lara31 [8.8K]3 years ago

8 0

Answer:

x = 12

Step-by-step explanation:

(whole secant) x (external part) = (whole secant) x (external part)

(6+x) *6 = (4+23) * 4

(6+x) *6 = 27*4

6(6+x) = 108

Divide each side by 6

6+x =18

Subtract 6 from each side

6+x-6 =18-6

x = 12

marta [7]3 years ago

8 0

The answer will be x=2

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The volume of sphere is increaseing

Artemon [7]

Volume of a sphere:

V = 4/3 π r ³

Differentiate V with respect to time t :

dV/dt = 4π r ² dr/dt

Surface area of a sphere:

A = 4π r ²

Differentiate A with respect to t :

dA/dt = 8π r dr/dt

You're given that the volume is increasing at a constant rate, dV/dt = 10 cm³/s, so

10 cm³/s = 4π r ² dr/dt

Solve for dr/dt (the rate of change of the sphere's radius):

dr/dt = 5/(2π r ²) cm³/s

Substitute this into the equation for dA/dt :

dA/dt = 8π r (5/(2π r ²) cm³/s)

dA/dt = 20/r cm³/s

At the moment the radius is r = 5 cm, the surface area is increasing at a rate of

dA/dt = 20/(5 cm) cm³/s = 4 cm²/s

When the surface area is increasing at a rate of dA/dt = 2 cm²/s, the radius r is such that

2 cm²/s = 20/r cm³/s

which happens when the radius is

r = 20/2 (cm³/s) / (cm²/s) = 10 cm

4 0

3 years ago

Find the limit of the function by using direct substitution.

serg [7]

Answer:

Option a.

$\lim_{x \to \frac{\pi}{2}}(3e)^{xcosx}=1$

Step-by-step explanation:

You have the following limit:

$\lim_{x \to \frac{\pi}{2}{(3e)^{xcosx}$

The method of direct substitution consists of substituting the value of $\frac{\pi}{2}$ in the function and simplifying the expression obtained.

We then use this method to solve the limit by doing $x=\frac{\pi}{2}$

Therefore:

$\lim_{x \to \frac{\pi}{2}}{(3e)^{xcosx} = \lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}cos(\frac{\pi}{2})}$

$cos(\frac{\pi}{2})=0\\$

By definition, any number raised to exponent 0 is equal to 1

$\lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}cos(\frac{\pi}{2})} = \lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}(0)}\\\\$

$\lim_{x\to \frac{\pi}{2}}{(3e)^{0}} = 1$

Finally

$\lim_{x \to \frac{\pi}{2}}(3e)^{xcosx}=1$

6 0

3 years ago

I’m soooo confused someone please helppppp!!

Ganezh [65]

Answer:

m>-5

Why? because the arrow shows -5 less then any number going right

Hope this helps

7 0

3 years ago

Angles E and G are

mash [69]

A and b as I believe

4 0

3 years ago

What is the area of this figure?

insens350 [35]

Answer:

54 units squared

Step-by-step explanation:

You have to divide the shape into simpler shapes such as rectangles and triangles that you can easily find the area of. Then, add those areas together. I divided it into one rectangle and three triangles.

Rectangle 1: length=7 width=6 6(7)=42

Triangle 1: base=6 height=2 1/2(6)2=6

Triangle 2: base=3 height=2 1/2(3)2=3

Triangle 3: base=6 height=1 1/2(6)1=3

Area= R1+T1+T2+T3= 42+6+3+3= 54 units squared

5 0

3 years ago

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