Answer:
9p⁸ + 12p⁴q⁴ + 4q⁸
Step-by-step explanation:
(3p⁴ + 2q⁴)² ⇒ The square of (3p⁴ + 2q⁴)
Squares are such bases that multiply itself two times.
⇒ (3p⁴ + 2q⁴)(3p⁴ + 2q⁴)
<u>Simplifying the expression using (a + b)(a + b) = (a x a) + (ab) + (ab) + (b²)</u>
⇒ (9p⁸ + 6p⁴q⁴ + 6p⁴q⁴ + 4q⁸)
⇒ (9p⁸ + 12p⁴q⁴ + 4q⁸) = 9p⁸ + 12p⁴q⁴ + 4q⁸
Answer:
d= 4
Step-by-step explanation:
The answer is C 52 degrees
A)Plugging in our initial statement values of y = 16 when x = 10, we get:
16 = 10k
Divide each side by 10 to solve for k:
16/10=
k = 1.6
Solve the second part of the variation equation:
Because we have found our relationship constant k = 1.6, we form our new variation equation:
y = 1.6x
Since we were given that x, we have
y = 1.6()
y = 0
B)Plugging in our initial statement values of y = 1 when x = 15, we get:
1 = 15k
Divide each side by 15 to solve for k:
1/15
=15k
k = 0.066666666666667
The discriminant of this solution is 76.
