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41=12d-7 what is the value of d in this equation
1 answer:
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Answer:
f(x) = 12x³ - 19x² + 17x - 17
Step-by-step explanation:
We can the numerator by multiplying the denominator by the quotient, and then adding the remainder.
We're given a denominator of 4x - 5
a quotient of 3x² - x + 3
and a remainder of -2
so the original numerator is:
(4x - 5)(3x² - x + 3) - 2
= 12x³ - 4x² + 12x - 15x² + 5x - 15 - 2
= 12x³ - 19x² + 17x - 17
Let's test that by dividing it by 4x -5 with long division:
That matches, so we know our answer's right, and:
f(x) = 12x³ - 19x² + 17x - 17
x= -0.25 and 1.25
x = -0.5 and 1.5
x = 0 and 1
x = -0.375 and 1.625
Step-by-step explanation:
Given equation of the curve is
(i)
First equation
Here y = 0
In x-axis the value of y = 0
The graph cuts the x-axis at(-0.25,0) and (1.25,0)
So, x= -0.25 and 1.25
(ii)
here y = 2
The line y= 2 cuts the curve at (-0.5,2) and (1.5,2)
So, x = -0.5 and 1.5
Given equation of the curve is
(i)
Here y = -1
The line y = -1 cuts the curve at (0,-1) and (1,-1)
So x = 0 and 1
(ii)
Here y = x+1
The line y -x =1 cuts the curve at (-0.375,0.5) and (1.625,2).
So x = -0.375 and 1.625