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Dmitriy789 [7]
3 years ago
5

Fifty balls numbered 1 through 50 are mixed up in a barrel. How many balls must you draw from the barrel (without looking) to be

sure that you have two even-numbered balls?
Mathematics
1 answer:
ipn [44]3 years ago
8 0
If you draw only 25 balls, you could draw the 25 odd-numbered balls.  However, there will then be no odd-numbered balls left, so when you draw two more you will be guaranteed to get two even-numbered balls.  Thus, the minimum is 25+2=27 balls.
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Identify the common factors of each set of numbers.<br> 1. 12 and 20<br> 2. 24 and 30
nevsk [136]

Answer:

The common factors of 12 and 20 are 4 and the common factors of 24 and 30 are 6.

Step-by-step explanation:

8 0
3 years ago
If = 20, then p=<br> O A) 20-5 5<br> OB) 20 x 5<br> O'C) 20 + 5<br> OD) 20/5
nikklg [1K]
It’s A, 20-5 5

P=20-5 5
3 0
3 years ago
If 64x=82, what is the value of x?<br> Round your answer to three places.
labwork [276]

Answer:

1.28

Step-by-step explanation:

First, you need to do 82/64, which will give you just x. Then, you need to round to three places. Without rounding it would be 1.28125

So with rounding it would be 1.28. Hope this helps and Happy learning!

3 0
2 years ago
Apply the junction rule to the junction labeled with the number 1 (at the bottom of the resistor of resistance R2R2R_2). Answer
Ira Lisetskai [31]

Answer:

-I₁ + I₂ + I₃ = 0

I₁ = I₂ + I₃

Step-by-step explanation:

The image of the circuit is obtained online and attached to the question.

The junction rule is essentially a law of conservation of current (charges). It applies to electrical circuits at steady state.

It explains that the for any given junction (node in an electrical circuit), the sum of current entering the junction is equal to the sum of current leaving the junction. That is, the net sum of current at any junction is zero.

Current entering a junction is assigned a positive sign and that leaving the junction is assigned a negative sign.

Σ I = 0

From the image of the circuit attached, I₁ is leaving the junction labelled number 1 and I₂ and I₃ are entering the junction.

Hence,

-I₁ + I₂ + I₃ = 0

I₁ = I₂ + I₃

Hope this Helps!!!

5 0
3 years ago
Determine the inverse of the function. (show work please)
uysha [10]

Answer:

This is easy -- it's just a list of steps.  At this level, the problems are pretty simple.

Let's just do one, then I'll write out the list of steps for you.

Find the inverse of f( x ) = -( 1 / 3 )x + 1

STEP 1:  Stick a "y" in for the "f(x)" guy:

y = -( 1 / 3 )x + 1

STEP 2:  Switch the x and y

                   ( because every (x, y) has a (y, x) partner! ):

x = -( 1 / 3 )y + 1

STEP 3:  Solve for y:

x = -( 1 / 3 )y + 1 ... multiply by 3 to ditch the fraction ... 3x = -y + 3 ... ditch the +3 ... subtract 3 from both sides ... 3x - 3 = -y ... multiply by -1 ... -3x + 3 = y ... y = -3x + 3

STEP 4:  Stick in the inverse notation, f^( -1 )( x )

f^( -1 )( x ) = -3x + 3

Step-by-step explanation:

5 0
3 years ago
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