17X-7Y. You add or subtract the same variables, in this case you only have two x's and one y. So you add them, because you have a addition sign. 13x+4x and you leave the Y alone, because there is not another Y variable.
Collect like terms
3g+11g-9-21
Add the like terms up
14g-30
if u have to simplify further, u have
2(7g-15)
Answer:
s=750+30W, after 14 weeks she has 1170$
Step-by-step explanation:
Answer:
54° and 110°
Step-by-step explanation:
The opposite angles of a cyclic quadrilateral are supplementary, sum to 180°
(9)
19x - 26 + 7x - 2 = 180
26x - 28 = 180 ( add 28 to both sides )
26x = 208 ( divide both sides by 26 )
x = 8
Then
∠ EFG = 7x - 2 = 7(8) - 2 = 56 - 2 = 54°
(10)
21x - 33 + 14x + 3 = 180
35x - 30 = 180 ( add 30 to both sides )
35x = 210 ( divide both sides by 35 )
x = 6
Then
∠ YVW = 14x + 3 = 14(6) + 3 = 84 + 3 = 87°
The inscribed angle YVW is half the measure of its intercepted arc YW, so
arc YW = 2 × 87° = 174°, then
arc XW = 174° - 64° = 110°
We need to 'standardise' the value of X = 14.4 by first calculating the z-score then look up on the z-table for the p-value (which is the probability)
The formula for z-score:
z = (X-μ) ÷ σ
Where
X = 14.4
μ = the average mean = 18
σ = the standard deviation = 1.2
Substitute these value into the formula
z-score = (14.4 - 18) ÷ 1..2 = -3
We are looking to find P(Z < -3)
The table attached conveniently gives us the value of P(Z < -3) but if you only have the table that read p-value to the left of positive z, then the trick is to do:
1 - P(Z<3)
From the table
P(Z < -3) = 0.0013
The probability of the runners have times less than 14.4 secs is 0.0013 = 0.13%