Answer:
<h2>210 gaL 60 % Antifreeze II</h2>
Step-by-step explanation:
In the problem, there are two types of antifreeze
antifreeze I and
antifreeze II
antifreeeze I 20 ----70 gal
Antifreeze II 60 ----- x gal
Total 50 ---------------- (70 + x ) gal
20*70+60*x=50(70+x)
1400+60x=3500+50x
60x-50x=3500-1400
10x=2100
x= 210
x=210 gaL 60 % Antifreeze II
Answer:
B
Step-by-step explanation:
x=4 so
2x4=8
8+5=13
Carlos's sister is 4 years old, therefore it is B.
Answer:
100
Step-by-step explanation:
thanks
Answer:
(a) k = C + 273.15, F = 1.8(k - 273.15) + 32
(b) k = 296.15
(c) 25 celcius is greater than 300 kelvis.
Step-by-step explanation:
(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.
C = k - 273.15
C + 273.15 = k
k = C + 273.15
F = 1.8(k - 273.15) + 32
(b) for this one you have to substitute in the previous equation and solve for k.
23 = k - 273.15
k = 23 + 273.15
k = 296.15
(c) you have to convert either kelvins to celcius or celcius to kelvins.
C = k - 273.15
C = 300 - 273.15
C = 26.85
So 25 celcius is greater than 300 kelvis.
