It takes the car 14 seconds to stop
Explanation:
A car is traveling at a constant velocity of 19 m/s when the driver puts
on the brakes to accelerate it at -1.4 m/s² until stopped
1. The initial velocity is 19 m/s
2. The acceleration is -1.4 m/s²
3. The final velocity is zero
We need to find how long it takes the car to stop
We can find the time by using the rule
→ v = u + a t
where v is the final velocity, u is the initial velocity, a is the
acceleration and t is the time
→ v = 0 m/s , u = 19 m/s , a = -1.4 m/s²
Substitute these values in the rule
→ 0 = 19 + (-1.4) t
→ 0 = 19 - 1.4 t
Add 1.4 t to both sides
→ 1.4 t = 19
Divide both sides by 1.4
→ t = 13.57 ≅ 14 seconds
It takes the car 14 seconds to stop
Learn more:
You can learn more about velocity in brainly.com/question/10772739
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To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:
Where,
= Mass of each object
= Initial Velocity of Each object
= Final Velocity
Our values are given as
Replacing we have that
Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s
Answer:
Phenomena is the plural form of Phenomenon.
A phenomenon is an extraordinary occurrence or circumstance.
Flowing water. As a turbine is creating energy, as is a generator and a reservoir just holds still water. Flowing water can be pumped through a turbine or hydro scheme and be turned into energy. Another thing, as it says potential, it’s referring to something that could be/isn’t yet
Answer:
kinematic viscosity in SUS is = 671.64 SUS
Explanation:
given data
kinetic viscosity = 145 mm^2/s
we know
1 mm = 0.1 cm
so kinetic viscosity in cm is 
other unit of kinetic viscosity is centistokes
so 1.45 cm^2/s will be 145 cst
if the temperature is 260°f , then cst value should be multiplied by 4.632. therefore kinematic viscosity in SUS is = 4.362 *145 = 671.64 SUS
