7. What does the changing colour perceived by the person as the filter changes indicate to you

Okay please help me all my assignments are due tomorrow! I need to know 5 examples of all 6 simple machines that can be found in

iren [92.7K]

Answer:

Inclined Plane – A ramp, for example a wheelchair ramp. Paired inclined planes make a pitched roof.

Wheel & Axle – On lawnmowers and wheelbarrow. Also, found in cabinet door glides and on appliances. Another common example – door knobs and even inside those locksets.

Lever – The bottle opener. Tools – the crowbar, and scissors or pliers. Double Levers – a door, a toilet seat, a broom.

Pulley – Old wood windows, some garage doors, workshop or garage lifting systems.

Wedge – The shim – used throughout the home in construction. For example, when installing doors, windows, cabinets, etc. Sometimes used to level furniture or chairs.

Screw – Like the wedge, above, well, you couldn’t build a house without screws. Certain types of plumbing valves. Plus, a jar lid is a popular example.

Now for deeper look at the simple machines found around our homes.

The hope this will be helpful.

3 0

3 years ago

A hockey stick moves toward a puck sitting on ice. A blue arrow labeled A points up from the puck. A blue arrow labeled F subscr

Lunna [17]

Answer:

normal force, the pluck will move off in a different direction

Explanation:

7 0

3 years ago

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A warehouse worker is pushing a 90.0-kg crate with a horizontal force of 282 N at a speed of v = 0.850 m/s across the warehouse

Elanso [62]

Answer:

$v_{f} = 0.51 \frac{m}{s}$

Explanation:

We apply Newton's second law at the crate :

∑F = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Data:

m=90kg : crate mass

F= 282 N

μk =0.351 :coefficient of kinetic friction

g = 9.8 m/s² : acceleration due to gravity

Crate weight (W)

W= m*g

W= 90kg*9.8 m/s²

W= 882 N

Friction force : Ff

Ff= μk*N Formula (2)

μk: coefficient of kinetic friction

N : Normal force (N)

Problem development

We apply the formula (1)

∑Fy = m*ay , ay=0

N-W = 0

N = W

N = 882 N

We replace the data in the formula (2)

Ff= μk*N = 0.351* 882 N

Ff= 309.58 N

We apply the formula (1) in x direction:

∑Fx = m*ax , ax=0

282 N - 309.58 N = 90*a

a= (282 N - 309.58 N ) / (90)

a= - 0.306 m/s²

Kinematics of the crate

Because the crate moves with uniformly accelerated movement we apply the following formula :

vf²=v₀²+2*a*d Formula (3)

Where:

d:displacement in meters (m)

v₀: initial speed in m/s

vf: final speed in m/s

a: acceleration in m/s²

Data

v₀ = 0.850 m/s

d = 0.75 m

a= - 0.306 m/s²

We replace the data in the formula (3)

vf²=(0.850)²+(2)( - 0.306 )(0.75 )

$v_{f} = \sqrt{(0.850)^{2} +(2)( - 0.306 )(0.75 )}$

$v_{f} = 0.51 \frac{m}{s}$

8 0

3 years ago

While trying out for the position of pitcher on your high school baseball team, you throw a fastball at 87.6 mi/h toward home pl

JulijaS [17]

The ball drops about 1 m.

8 0

3 years ago

What is the moment of inertia i of this assembly about the axis through which it is pivoted? Express the moment of inertia in te

charle [14.2K]

Answer:

I = x^2(m1+m2+1/3mr)

Explanation:

8 0

3 years ago

Read 2 more answers