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soldier1979 [14.2K]
3 years ago
13

Which formula can be used to find the nth term of a geometric sequence where the fifth term is 1/16 and the common ratio is 1/4

?
Mathematics
2 answers:
CaHeK987 [17]3 years ago
7 0

Answer:

a₅ = 16(1/4)⁴

Step-by-step explanation:


stepladder [879]3 years ago
4 0
A₅ = 1/16  and r= 1/4

Let see how to build up this formula that is going to give that term of rank n

1st term =a₁ = To be calculated

1st a₁   = a₁  x  r°
2nd a₂  = a₁  x  r¹
3rd a₃  =  a₁  x  r²
4th a₄   = a₁  x  r³
5th a₅   = a₁  x  r⁴
.......................
.......................
nth : a(n) = a₁  x r⁽ⁿ-¹)
Note when that the subscript of a is the same as the exponent mines 1

We know the ratio r =1/4 & the fifth term, a₅ =1/16 (given). Now let's apply the formula to calculate the unknown a₁.

a(n) = a₁  x r⁽ⁿ-¹) ==>a₅ = a₁ x (1/4)⁽⁵⁺¹⁾ ===> 1/16 = a₁ x (1/4)⁴
1/167 = a₁ (1/256) ==> a₁ =16 & the formula becomes
a₅ = 16(1/4)⁴

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An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2000 individ
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a) P=0.558

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Step-by-step explanation:

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a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:

P(4\leq x\leq 9)=\sum_{k=4}^9P(k)\\\\\\ P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\P(9)=4^{9} \cdot e^{-4}/9!=262144*0.0183/362880=0.013\\\\\\

P(4\leq x\leq 9)=\sum_{k=4}^9P(k)=0.195+0.156+0.104+0.060+0.030+0.013=0.558

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P(x\geq9)=1-P(x\leq 8)\\\\\\

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Answer:

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Step-by-step explanation:

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