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3 years ago

A retired man gets paid 4/5 of his regular salary. If his retirement pay amounts to $28,000, what was his regular salary?

Mathematics

1 answer:

Semmy [17]3 years ago

5 0

The correct answer would be A.

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The expression 2y + 2.7 is equal to for y = 4.

Darya [45]

Answer:

10.7

Step-by-step explanation:

i am not certain but since y is the 4 you will have 2(4) + 2.7 so you get 8+2.7 since you do 2x4 then you add 8 and 2.7 to get 10.7

6 0

3 years ago

the equation y = 1/5x represents a proportional relationship. explain how you can tell the relationship is proportional from the

Pachacha [2.7K]

Answer:

Yes, y = $\frac{1}{5}$ x represents a proportional relationship and the constant of proportionality is $\frac{1}{5}$

Step-by-step explanation:

The Proportional is a relationship between two quantity one of them equals the product of the other and a constant, where this constant called the constant of proportionality

If x and y are proportion, then y = k x, where k is the constant of proportionality

The proportional relationship represented graphically by a line passing through the origin point (0, 0)

Let us solve the question

∵ y = $\frac{1}{5}$ x

→ It the same as the form of the proportional equation above

∵ $\frac{1}{5}$ is a constant

∴ y is the product of x and constant

∴ y = $\frac{1}{5}$ x represents a proportional relationship

Substitute x by 0 to find y and show it represented by a line passing through the origin

∵ x = 0

∴ y = $\frac{1}{5}$ (0) = 0

→ That means point (0, 0) lies on the line which represents the equation

∴ The line which represents this relation is passing through the origin

∴ y = $\frac{1}{5}$ x represents a proportional relationship

∵ y = kx, k is the constant of proportionality

∵ y = $\frac{1}{5}$ x

∴ k = $\frac{1}{5}$

∴ The constant of proportionality is $\frac{1}{5}$

5 0

4 years ago

Suppose that Drake works for a research institute in Greenland and is given the job of treating wild polar bears there for hypot

kvv77 [185]

Step-by-step explanation:

Check the attached file for solution and

simulation screen shot

R-Code:

Sample mean

sd = 60 Population Standard deviation

n = 10 Sample size

conf.level = 0.99 Confidence level

$\alpha = 1-conf.level$

$z\star = \round(\qnorm(1-\alpha/2),2); z.\star$

$E = \round(z* \times \sigma/\sqrt(n),2); E$

$x= c(E,-E)$

7 0

4 years ago

In the midpoint rule for triple integrals we use a triple riemann sum to approximate a triple integral over a box b, where f(x,

Lana71 [14]

The sub-boxes will have dimensions $\frac{2-0}{2} \times \frac{2-0}{2} \times \frac{2-0}{2} =1\times1\times1=1 \ cubic \ units$

x sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $x= \frac{1}{2}$ and $x= \frac{3}{4}$
y sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $y= \frac{1}{2}$ and $y= \frac{3}{4}$
z sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $z= \frac{1}{2}$ and $z= \frac{3}{4}$ 

Let $f(x,y,z)=\cos{(xyz)}$

$\int\limits \int\limits \int\limits {f(x,y,z)} \, dV \approx f\left( \frac{1}{2} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{3}{4} \right)$
$+f\left( \frac{3}{4} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{3}{4} \right) \\ \\ \approx\cos{ \frac{1}{8} }+\cos{ \frac{3}{16} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{9}{32} }+\cos{ \frac{27}{64} } \\ \\ \approx0.9922+0.9825+0.9825+0.9607+0.9825+0.9607+0.9607 \\ +0.9123 \\ \\ \approx\bold{7.734}$

5 0

3 years ago

Please help WILL MARK BRAINLIEST I need the right answer

LUCKY_DIMON [66]

Answer: a

Step-by-step explanation:

6 0

3 years ago