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Brrunno [24]
3 years ago
6

A retired man gets paid 4/5 of his regular salary. If his retirement pay amounts to $28,000, what was his regular salary?

Mathematics
1 answer:
Semmy [17]3 years ago
5 0
The correct answer would be A.
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The expression 2y + 2.7 is equal to for y = 4. ​
Darya [45]

Answer:

10.7

Step-by-step explanation:

i am not certain but since y is the 4 you will have 2(4) + 2.7 so you get 8+2.7 since you do 2x4 then you add 8 and 2.7 to get 10.7

6 0
3 years ago
the equation y = 1/5x represents a proportional relationship. explain how you can tell the relationship is proportional from the
Pachacha [2.7K]

Answer:

Yes, y = \frac{1}{5} x represents a proportional relationship and the constant of proportionality is \frac{1}{5}

Step-by-step explanation:

<em>The Proportional is a relationship between two quantity one of them equals the product of the other and a constant, where this constant called the constant of proportionality </em>

  • If x and y are proportion, then y = k x, where k is the constant of proportionality
  • The proportional relationship represented graphically by a line passing through the origin point (0, 0)

Let us solve the question

∵ y = \frac{1}{5} x

→ It the same as the form of the proportional equation above

∵  \frac{1}{5}  is a constant

∴ y is the product of x and constant

∴ y =  \frac{1}{5} x represents a proportional relationship

Substitute x by 0 to find y and show it represented by a line passing through the origin

∵ x = 0

∴ y = \frac{1}{5} (0) = 0

→ That means point (0, 0) lies on the line which represents the equation

∴ The line which represents this relation is passing through the origin

∴ y = \frac{1}{5} x represents a proportional relationship

∵ y = kx, k is the constant of proportionality

∵ y = \frac{1}{5} x

∴ k =  \frac{1}{5}

∴ The constant of proportionality is \frac{1}{5}

5 0
4 years ago
Suppose that Drake works for a research institute in Greenland and is given the job of treating wild polar bears there for hypot
kvv77 [185]

Step-by-step explanation:

<em>Check the attached file for solution and </em>

<em>simulation screen shot</em>

R-Code:

Sample mean

sd = 60 Population Standard deviation

n = 10 Sample size

conf.level = 0.99 Confidence level

\alpha = 1-conf.level

z\star = \round(\qnorm(1-\alpha/2),2); z.\star

E = \round(z* \times \sigma/\sqrt(n),2); E

x= c(E,-E)

7 0
4 years ago
In the midpoint rule for triple integrals we use a triple riemann sum to approximate a triple integral over a box b, where f(x,
Lana71 [14]
<span>The sub-boxes will have dimensions \frac{2-0}{2} \times \frac{2-0}{2} \times \frac{2-0}{2} =1\times1\times1=1 \ cubic \ units

x sub-intervals are 0 to 1 and 1 to 2. Midpoints are at x= \frac{1}{2} and </span><span>x= \frac{3}{4}
y sub-intervals are 0 to 1 and 1 to 2. Midpoints are at </span><span>y= \frac{1}{2} and </span><span>y= \frac{3}{4}
z sub-intervals are 0 to 1 and 1 to 2. Midpoints are at </span><span>z= \frac{1}{2} and </span><span><span>z= \frac{3}{4}</span>

Let f(x,y,z)=\cos{(xyz)}

\int\limits  \int\limits  \int\limits {f(x,y,z)} \, dV \approx f\left( \frac{1}{2} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{3}{4} \right)
+f\left( \frac{3}{4} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{3}{4} \right) \\  \\ \approx\cos{ \frac{1}{8} }+\cos{ \frac{3}{16} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{9}{32} }+\cos{ \frac{27}{64} } \\  \\ \approx0.9922+0.9825+0.9825+0.9607+0.9825+0.9607+0.9607 \\ +0.9123 \\  \\ \approx\bold{7.734}</span>
5 0
3 years ago
Please help WILL MARK BRAINLIEST I need the right answer​
LUCKY_DIMON [66]

Answer: a

Step-by-step explanation:

6 0
3 years ago
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