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Phoenix [80]
3 years ago
8

The following probabilities are based on data collected from U.S. adults during the National Health Interview Survey 2005-2007.

Individuals are placed into a weight category based on weight, height, gender and age. Underweight Healthy Weight Overweight (Not Obese) Obese Probability 0.019 0.377 0.35 0.254 Based on this data, what is the probability that a randomly selected U.S. adult who weighs more than the healthy weight range is obese? 0.421
Mathematics
1 answer:
Nutka1998 [239]3 years ago
8 0

Answer:

Required Probability  =0.421  

Step-by-step explanation:

Let's first arrange the data given in a more presentable way: So, we have the following probabilities for different categories.

Underweight (UW) = 0.019

Healthy Weight (HW) = 0.377

Overweight but Not Obese (NO) = 0.35

Obese (O) = 0.254

<em>Now, let's calculate the probability that a randomly selected American adult who weighs more than the healthy weight range is obese:</em>

Required Probability = Probability(obese)/Probability(Overweight + Obese)

                                    = P (O) /P(NO + O)                                  

                                    =0.254/(0.35+0.254)

Required Probability  =0.421

where, O for Obese and NO for Not Obese or Overweight but Not Obese.

So, the correct answer = 0.421

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The function(t)--4.87+18.75 is used to model the height of an object projected in the air, where h() is the height in
NNADVOKAT [17]

The domain and range of the given function are equal to (0, 3.85) and (0, 18.75) respectively.

<h3>How to calculate the domain of the function?</h3>

In this exercise, you're given the following function h(t) = -4.87t² + 18.75t. Next, we would equate the function to zero (0) to determine its domain as follows:

0= -4.87t² + 18.75t.

4.87t(-t + 3.85) = 0

t = 0 or t = 3.85.

Therefore, the domain is 0 ≤ t ≤ 3.85 or (0, 3.85).

<h3>How to calculate the range of the function?</h3>

h(t) = -4.87t² + 18.75t

h(t) = -4.87(t² - 3.85t + 3.85 - 3.85)

h(t) = -4.87(t - 1.925)² + 18.05

Therefore, the range is 0 ≤ h ≤ 18.05 or (0, 18.75).

Read more on domain here: brainly.com/question/17003159

#SPJ1

3 0
2 years ago
Read 2 more answers
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