Question

Allie fires a rocket from ground level. The height of the rocket is given by the formula h= 260t - 16t^2 (-16t squared), where t is the time in seconds after launch. How long will the rocket be in the air?

Answer 1

Answer:

The rocket would be in the air for 8.125 seconds after launch.

Step-by-step explanation:

Given that the height of the rocket, h = 260t - 16$t^{2}$.

To determine how long the rocket would be in the air, differentiate h totally with respect to t.

So that, total derivative of h is given as;

$\frac{dh}{dt}$ = $\frac{d(260t-16t^{2}) }{dt}$

0 = 260 - 16 x 2t

  = 260 - 32t

0 = 260 - 32t

32t = 260

t = $\frac{260}{32}$

 = 8.125

t= 8.125 seconds

The rocket would be in the air for 8.125 seconds after launch.