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gogolik [260]
3 years ago
5

Allie fires a rocket from ground level. The height of the rocket is given by the formula h= 260t - 16t^2 (-16t squared), where t

is the time in seconds after launch. How long will the rocket be in the air?
Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

The rocket would be in the air for 8.125 seconds after launch.

Step-by-step explanation:

Given that the height of the rocket, h = 260t - 16t^{2}.

To determine how long the rocket would be in the air, differentiate h totally with respect to t.

So that, total derivative of h is given as;

\frac{dh}{dt} = \frac{d(260t-16t^{2}) }{dt}

0 = 260 - 16 x 2t

  = 260 - 32t

0 = 260 - 32t

32t = 260

t = \frac{260}{32}

 = 8.125

t= 8.125 seconds

The rocket would be in the air for 8.125 seconds after launch.

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