Think very hard about this question what do I do first how do I do this the answer will come if you ask the right question
The ratio of length to width is 3/2. Let's set up equations of ratios using first the 25 cm length of the paper and then the 20 cm width:
3 25 cm
--- = ----------
2 x
Solving for x, 3x = 50 cm, and x =16 2/3 cm. This is possible, since 16 2/3 is less than the paper width 20 cm.
3 20 cm
--- = -----------
2 x
Solving for x: 3x = 40 cm; x = 40/3 cm, or x= 13 1/3 cm. This is possible, but does not make maximum use of the 20 by 30 cm paper.
Answer: the largest flag Jake can draw on the paper given is 20 cm (length) by 16 2/3 cm.
The difference is that evaluating an expression for a given value is an example of let’s say In a example, the variable x is equal to 6 since 6 + 6 = 12. So it means that they are giving you the input already. SOLVING an equation is working backwards, to undo everything that has been done to the input. So you have to do the equation in order to find your answer.
Since there are no specific requirements given other than expression written using exponents, I am just going to give some examples.
1. 5x^2 - 3
2. 8^5 - 15x + 7
3. 15x^10 - 8x^7 + 16x^5 + 17^3 - 4^2 +13x - 2
Answer:
1st quartile is 136
The second quartile is also the median 142
The third quartile is 162
The interquartile range is the difference between the 3rd and first quartile or 26
Step-by-step explanation:
