Answer:
And if we solve for a we got
And the limits for this case are: (214.4; 295.4)
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the annual precipitation of a population, and for this case we know the distribution for X is given by:
Where
and
The confidence level is 95.44 and the signficance is
and the value of
. And the critical value for this case is 
Using this condition we can find the limits
And if we solve for a we got
And the limits for this case are: (214.4; 295.4)
Weight of an grapefruit=weight of an orange+8% weight of an orange
weight of an apple=weight of an orange -10% weight of an orange
a.<span>By what percentage is the grapefruit heavier than the apple?
We should find the connection between grapefruit and an apple. We know the connection between the weight of a grapefruit and an orange, we know the connection between an orange and an apple, so this means we know the connection between a grapefruit and an apple.
</span>
weight of an grapefruit=weight of an <span>orange+8% weight of an orange
</span>weight of an orange=weight of an apple<span> +10% weight of an apple
</span>
-> weight of an grapefruit=weight of an apple+10% weight of an apple + 8%(weight of an apple+10% weight of an apple)= weight of an apple + 18% weight of an apple + 2% weight of an apple= <span>weight of an apple + 20% weight of an apple
</span><span>b.By what percentage is the apple lighter than the grapefruit?
</span>weight of an grapefruit=weight of an apple + 20% weight of an apple<span>
</span>
-> The apple ts 20% lighter than the grapefruit.
Answer:
Step-by-step explanation:
(7^0/7^5)^1/5
= (1 / 7^5)^ 1/5
= (7^-5)^1/5
= 7^-1
= 1/7 is the correct answer.
Since

, we know that

follows a Poisson distribution with parameter

.
Now assuming

denote the mean and standard deviation of

, respectively, then we know right away that

and

.
So,