Equation is 112= 14x
x= 8
mulan worked for 8 hours
Step-by-step answer:
Please refer to attached image.
1. Quad PQRS is cyclic (all vertices on the same circle), so opposite angles are supplementary, meaning
that
angles QPS and QRS are supplementary =>
QPS+QRS=180 =>
QRS = 180 - 74 = 106
2. Triangle RSQ is isosceles with RS=RQ =>
angles RSQ and RQS are congruent.
3. Angle RSQ = (180 - 106) /2 = 74 / 2 = 37
4. QP is a diameter => angle QSP is a right-angle.
5. From (3) and (4) above,
angle RSP = 37+90 = 127
6. Since PQRS is cyclic, angles RQP and RSP are supplementary =>
RQP+RSP = 180 =>
x + 127 = 180 =>
x = 180 - 127 = 53 degrees.
Answer:
the ans is C..... good luck
Answer:
Step-by-step explanation
The length of the left sloping line
= √ (5^2 + 7^2) = √74.
The right sloping line
= √(5^2 + 5^2) = √50.
So the perimeter:
= √74 + √50 + 2 + 2 * 4 + 14
= 39.67 to nearest hundreth.
Area = 1/2 * 5 * 7 + 2*5 + 1/2 * 5 * 5 + 4*14
= 96.
Answer:
I think it would be group B due to the fact that they are the closest to 25 g
Step-by-step explanation: