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Stella [2.4K]
4 years ago
10

People use data and statistics to help them make important policy decisions, to identify problems in an organization, and to pre

dict outcomes. In this unit, you studied various ways to analyze and represent data sets to determine how to best interpret the data. You also learned how to critically examine the data and account for outside factors that may influence the patterns you see in the data.
Think about the many statistical scores or rankings you receive in school, such as GPA, SAT and ACT scores, test scores, and class ranking. Describe the usefulness and limitations of these pieces of data in defining who you are as a person or as a student. In what ways do they help give a clear picture? What are they not conveying?


EXCEPT FOR THIS ANWSER , I NEED ANOTHER ONE

Well school is just a numbers thing , at school this is all that matters and all that defines you. I fyou get bad grades you're labeled stupid , It doesnt matter what the circumstances are in your life , your way of learning , or even your effort . None of that gets traken into account when looking at someones intelligence at school , yes grades are a good standard to see the level of intellect but it's ridiculous it';s the end all be all with schools and getting into college. Yes obviously grades are the most effective way to find out someones intellect but it is most for sure not the end all be all to level someones brains.
Mathematics
1 answer:
Liula [17]4 years ago
7 0

Answer:

Statistical scores and rankings are useful because they provide quantitative figures that represent the student's level of understanding. These methods of ranking can give the observer an opportunity to quickly analyze results but they leave out other factors that are both quantifiable and non-quantifiable. For example, the data won't explicitly convey the time an individual studies but it is compelling to say that good scores and time studying gave a linear relationship. An example of something that is non-quantifiable is the experiences and past knowledge that can affect how well an individual understands and tests on a specific subject.

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Create a function f(x) such that f(3)=20
svp [43]

Answer:

f(x) =  \frac{20}{3} x

Step-by-step explanation:

f(x) =  \frac{20}{3} x \:  ...  (required function)  \\ Plug \: x = 3 \\ f(3) =  \frac{20}{3}  \times 3 \\ f(3) = 20

5 0
3 years ago
Help me please <br> !!!!!!!!!!!!
Tpy6a [65]

Answer:

40

Step-by-step explanation:

Angle Formed by Tangent and Secant = 1/2 (DIFFERENCE of Intercepted Arcs)

< WVT = 1/2 ( WT - UW)

3x+4    = 1/2 (( 14x +7) - (7x+11))

Distribute

3x+4    = 1/2 ( 14x +7 - 7x-11)

Combine like terms

3x+4    = 1/2 ( 7x -4 )

Multiply each side by 2

6x +8 = 7x-4

Subtract 6x from each side

+8 = x-4

Add 4 to each side

12 =x

WVT = 3x+4

        = 3*12 +4

       = 36+4

       = 40

7 0
3 years ago
Find the surface area of the cube shown below
noname [10]

Answer:

the answer is 37.5cm^2

8 0
3 years ago
We are going to fence in a rectangular field that encloses 75 ft2. Determine the dimensions of the field that will require the l
pychu [463]

Answer:

For width W and length L, we have:

W = L = √(75ft^2) = 8.66ft

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = L*W

and the perimeter is:

P = 2*L + 2*W

First, we know that the area of our rectangle is:

A = 75ft^2 = L*W

And we want to minimize the perimeter of our rectangle, then we need to minimize:

P = 2*L + 2*W

From the equation:

75ft^2 = L*W

We can isolate one of the variables, let's isolate L

L = (75ft^2)/W

We could replace this in the perimeter equation:

P(W) = 2*( (75ft^2)/W) + 2*W

P(W) = (150 ft^2)/W + 2*W

To find the minimum of the perimeter we need to look at the zero of the first derivative of P(W).

P'(W) = dP(W)/dW = -(150ft^2)/W^2 + 2

Now we need to find the value of W such that:

P'(W) = 0

0 =  -(150ft^2)/W^2 + 2

(150 ft^2)/W^2 = 2

(150ft^2) = 2*W^2

(150ft^2)/2 = W^2

75 ft^2 = W^2

√(75ft^2) = W = 8.66ft

And remember that:

L =  (75ft^2)/W

replacing with W = √(75ft^2)

L =  (75ft^2)/√(75ft^2) = √(75ft^2)

Then:

W = L = √(75ft^2) = 8.66ft

6 0
3 years ago
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4 years ago
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