Answer:
0.645 L
Explanation:
To find the volume, you need to (1) convert grams to moles (using the molar mass) and then (2) calculate the volume (using the molarity ratio). The final answer should have 3 sig figs to match the sig figs of the given values.
(Step 1)
Molar Mass (KOH): 39.098 g/mol + 15.998 g/mol + 1.008 g/mol
Molar Mass (KOH): 56.104 g/mol
19.9 grams KOH 1 mole
-------------------------- x ----------------------- = 0.355 moles KOH
56.014 grams
(Step 2)
Molarity = moles / volume <----- Molarity ratio
0.550 M = 0.355 moles / volume <----- Insert values
(0.550 M) x volume = 0.355 moles <----- Multiply both sides by volume
volume = 0.645 L <----- Divide both sides by 0.550
Answer:
Cells are the basic building blocks of all living things.
The human body is composed of trillions of cells.
They provide structure for the body, take in nutrients from food, convert those nutrients into energy, and carry out specialized functions.
Cells have many parts, each with a different function.
I hope it helps....
<span>
</span>∴
=
= 0.0147 mol
1 : 1
∴
= 0.0147 mol
Mass = Molar Mass * Mol
∴
= [(23 * 2)+(65)+(16 * 4) + (1*4)] g/mol * 0.0147 mol
= 179 g/mol * 0.0147 mol
=
2.63 g
Why are Acetyl-CoA and succinyl-CoA, both high energy thioesters, chemical energies put to different uses?
The energy released by hydrolysis of acetyl-CoA is needed for the condensation reaction that links acetyl moiety to oxaloacetate, yielding citrate. The energy released by hydrolysis of succinyl-CoA drives the phosphorylation of GDP, yielding GTP
Some reactions of the citric acid cycle are endergonic. Explain how the overall cycle is exergonic.
The sum of the energies of the individual reactions is -44.3kJ for each mole of acetyl-CoA that enters the cycle
Which enzymes of the citric acid cycle are missing from the glyoxylate cycle?
isocitrate dehydrogenase, alpha-ketoglutarate dehydrogenase, and succinyl-CoA synthetase
For this question, we can use relations for pH and pOH. We calculate as follows:
pOH = -log [OH-]
pOH = -log [<span>1.83x10^-7 M]
pOH = 6.74
pH + pOH = 14
pH = 14 - 6.74
pH = 7.26
pH = -log [H3O+]
7.26 = -log[H3O+]
[H3O+] = 5.46 x 10^-8 M
Hope this answers the question. Have a nice day.</span>