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3 years ago

MnCl₂ (aq) + (NH₄)₂CO₃ (aq) --> MnCO₃ (s) + 2 NH₄Cl (aq)

Chemistry

2 answers:

LuckyWell [14K]3 years ago

8 0

this equation is balanced.

andrew-mc [135]3 years ago

8 0

Answer:

Nothing to do, is already balanced.

Explanation:

MnCl₂ (aq) + (NH₄)₂CO₃ (aq) --> MnCO₃ (s) + 2 NH₄Cl (aq)

Left Side

Mn =1

Cl = 2

N = 2

H = 8

C = 1

O = 3

Right Side

Mn =1

Cl = 2

N = 2

H = 8

C = 1

O = 3

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How many molecules of carbon dioxide are dissolved in 0.550 L of water at 25 °C if the pressure of CO2 above the water is 0.250

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To calculate the molar solubility, we use the equation given by Henry's law, which is:

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$K_H$ = Henry's constant = $0.034mol/L.atm$

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Putting values in above equation, we get:

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To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of carbon dioxide = $8.5\times 10^{-5}M$

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Putting values in above equation, we get:

$8.5\times 10^{-3}M=\frac{\text{Moles of }CO_2}{0.550L}\\\\\text{Moles of }CO_2=(8.5\times 10^{-3}mol/L\times 0.550L)=4.675\times 10^{-3}mol$

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1 mole of a compound contains $6.022\times 10^{23}$ number of molecules

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Hence, the number of molecules of carbon dioxide gas are $2.815\times 10^{21}$

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