There are 25 $10 bills and 11 $20 bills.
Step-by-step explanation:
Given,
Worth of proceeds from garage = $470
Let,
x be the number of $10 bills
y be the number of $20 bills.
According to given situation;
10x+20y=470 Eqn 1
x = y+14 Eqn 2
Putting value of x from Eqn 2 in Eqn 1

Dividing both sides by 30

Putting y=11 in Eqn 2

There are 25 $10 bills and 11 $20 bills.
Keywords: linear equation, substitution method
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The confidence interval for the mean usage of water is (18.7,20.5).
Given population standard deviation of 2.4, mean of 19.5 gallons per day and confidence interval of 98%.
We have to find the confidence interval for the mean usage of water.
To find out the confidence interval we have to first find margin of error.
μ=19.5
σ=2.4
α=0.98
α/2=0.49
We have to find the z value for the p value 0.49 which is z=2.33
Margin of error=z*μ/
=2.33*19.5/
=0.82
lower level=mean -m
=19.5-0.82
=18.68
after rounding upto 1 decimal
=18.7
upper mean = mean+m
=19.5+0.82
=20.52
Hence the confidence interval for the usage of water is (18.7,20.52).
Learn more about margin of error at brainly.com/question/10218601
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Answer:
1³ = 1
2³ = 8
3³ = 27
4³ = 64
5³ = 125
6³ = 216
Step-by-step explanation:
4^x + 6^x = 9^x
4^x + 6^x - 9^x = 0
2^2x + (2×3)^x - 3^2x = 0
2^2x + 2^x×3^x - 3^2x = 0
(⅔)^2x + (⅔)^x - 1 = 0
let t = ( ⅔)^x
t² + t - 1 = 0
t = (-1+√5 ) / 2
(⅔)^x = (-1+√5 ) / 2
x = Log base ⅔ ((-1+√5 ) / 2 )
x = 1.18681
Essential h(40) is the equivalent of when y=40. Together, when y=40 x=1700, kind of like a coordinate pair (40, 1700).
-E :)