since BA ≅ BC, that means is an isosceles triangle, whose twin sides make twin angles at the <u>base</u>, namely the interior angles at A and C are both twin angles, and their exterior angles at those point are also twins, check the picture below.
that simply means that "x" and "y" are linear angles, therefore
x + y = 180°
117 + y = 180
y = 180 - 117
y = 63.
Answer:
Return of investment = 44.5%
Step-by-step explanation:
Number of shares purchased by Tamara = 1500
Offer price per share = 7. 08
Total amount spent on purchasing shares = 1500 × 7.08 = 10620
Dividend receive per share = 0.21
Total dividend received on 1500 shares = no. of shares × dividend received per share
Total dividend received = 1500 × 0.21 = 315
Selling price per share = 10.02
Amount received by Tamara by selling the investment = no. of shares × selling price per share
Amount received by Tamara by selling the investment
= 1500 × 10.02
= 15030
Now, Net profit received on investment = S.P of Investment + Dividend received - C.P of investment
Net profit = 15030 + 315 - 10620 = 15345 - 10620 = 4725
Return on investment = 
=
≈ 44.5 %
Answer:
7.5 miles
Step-by-step explanation:
to convert from 8km to 12km, multiply by 1.5.
Do the same to the other side, so 5 miles times 1.5 is 7.5 miles
$11.25 for a pack of paper plates, hope this helps
Answer:
The 95% confidence interval for the measurements is [48.106, 53.494].
Step-by-step explanation:
The average M of this sample is

The standard deviation s of this sample is

![s=\sqrt{\dfrac{1}{4}\cdot [(52-50.8)^2+(48-50.8)^2+(49-50.8)^2+(52-50.8)^2+(53-50.8)^2]}](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B%5Cdfrac%7B1%7D%7B4%7D%5Ccdot%20%5B%2852-50.8%29%5E2%2B%2848-50.8%29%5E2%2B%2849-50.8%29%5E2%2B%2852-50.8%29%5E2%2B%2853-50.8%29%5E2%5D%7D)
![s=\sqrt{\dfrac{1}{4}\cdot [(1.44)+(7.84)+(3.24)+(1.44)+(4.84)]}=\sqrt{\dfrac{18.8}{4}}=\sqrt{4.7}\\\\\\s=2.168](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B%5Cdfrac%7B1%7D%7B4%7D%5Ccdot%20%5B%281.44%29%2B%287.84%29%2B%283.24%29%2B%281.44%29%2B%284.84%29%5D%7D%3D%5Csqrt%7B%5Cdfrac%7B18.8%7D%7B4%7D%7D%3D%5Csqrt%7B4.7%7D%5C%5C%5C%5C%5C%5Cs%3D2.168)
The degrees of freedom are

Then, the critical value of t for a 95% CI and 4 degrees of freedom is t=2.776.
The margin of error of the CI is:

Then, the lower and upper bounds of the CI are:

The 95% confidence interval for the measurements is [48.106, 53.494].