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lorasvet [3.4K]
3 years ago
8

If HK = 4p - 51 and JK = p, find the value of p in parallelogram GHIJ, help !

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
5 0

Answer: Question not very clear

Step-by-step explanation:

I will like to see the original question, then I will attempt to help you. Surely.

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If you add the lengths of the focal radii of an ellipse, what other value will you produce?
ss7ja [257]

Equation of an ellipse

→having center (0,0) , vertex ((\pm a ,0) and covertex (\pm b ,0) and focus (\pm c ,0) is given by:

\frac{x^2}{a^2} + \frac{y^2}{b^2}=1

As definition of an ellipse is that locus of all the points in a plane such that it's  distance from two fixed points called focii  remains constant.

Consider two points (a,0) and (-a,0) on Horizontal axis of an ellipse:

Distance from (a,0) to (c,0) is = a-c = F_{1}

Distance from (-a,0) to (c,0) is = a + c = F_{2}

F_{1} + F_{2} = a -c + a +c

          = a + a

        = 2  a  →(Option A )


8 0
3 years ago
Read 2 more answers
The vertex angle of an isosceles triangle measures 42°. A base angle in the triangle has a measure given by
siniylev [52]

Answer:

the value of x=33

the measure of each base angle = 42 ,69,69

Step-by-step explanation:

Bases od isosceles triangles are congruent,so

2(2x+3)=4x+6 (This is the sum ob both anlgles base)

All angles in a triangle add to 180

4x+6 + 42 = 180

4x = 132

x=33

2(33)+3= 69

69+69+42 = 180

5 0
3 years ago
Read 2 more answers
Factorise 3<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="la
PilotLPTM [1.2K]
(x+1)x(3x+2) is the answer
5 0
3 years ago
What is the the volume of this?<br><br> Also you can explain just make the explanation short
fgiga [73]
15×20×10=3000
10×20×15=3000
3000+3000=6000 cm^{2}

6 0
3 years ago
ANSWER PLS URGENT VERY URGENT TYSM ik its a lot of questions but id really really be grateful for the help
anyanavicka [17]

Step-by-step explanation:

about circle R

arc angle MP = angle MRP = 78°

angle M = angle LMP.

according to the rules of inscribed angles, LMP is half of angle LRP.

LRP + MRP = 180° because together they cover the whole LM segment (half-circle).

LRP = 180 - MRP = 180 - 78 = 102°

so, LMP = angle M = 102/2 = 61°

also circle R (with arc ULNP)

the arc ULNP = arc UL + arc LN + arc NP = 160°

due to the congruent definition of JU and MP we know that arc UL = arc NP.

and we know arc LN = arc JM = 18°.

so,

160 = 2×arc NP + 18

142 = 2×arc NP

arc NP = 71° = arc UL

now, because arc MP + arc LP = 180 (half-circle),

arc MP = 180 - arc LP = 180 - arc LN - arc NP =

= 180 - 18 - 71 = 91°

about the circle R with 2 congruent chords :

the second answer : they are equidistant from R (the center of the circle).

about circle W

arc MK + arc KL = 180° (half-circle).

and we see

arc HL = arc KL = 53°.

so,

arc MK + 53 = 180°

arc MK = 180 - 53 = 127°

about circle M

arc QTS = 204°.

therefore, arc QRS = 360 - arc QTS = 360 - 204 =

= 156° = angle QMS.

according to the rules of inscribed angles

angle QTS = QMS/2 = 156/2 = 78°

4 0
2 years ago
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