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Ivenika [448]
3 years ago
15

The grades on a language midterm at Loyola are roughly symmetric with u = 69 and 0 = 4.0.

Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0

Answer:

Step-by-step explanation:

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What is the value of the expression 2.6x10^9 over 1.3x10^2
arsen [322]
2.6/1.3 * (10^9/10^2)
2*10^7
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Write the solution of the inequality in set builder notation 7-3d&gt;28
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D<-7 
{d | d<-7}
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H function is even, odd, or neither.<br> b. g(x) = x² - 2<br> Is it odd or even
o-na [289]

g(x) = x^2 - 2 \text{ is even function }

<em><u>Solution:</u></em>

Given that,

g(x) = x^2 - 2

We have to find whether the above function is odd or even

If a function is: y = f(x)

If f(-x) = f(x), the function is even

If f(-x) = - f(x), the function is odd

Which is,

\mathrm{Even\:Function:\:\:A\:function\:is\:even\:if\:}f\left(-x\right)=f\left(x\right)\mathrm{\:for\:all\:}x\in \mathbb{R}\\\\\mathrm{Odd\:Function:\:\:A\:function\:is\:odd\:if\:}f\left(-x\right)=-f\left(x\right)\mathrm{\:for\:all\:}x\in \mathbb{R}

From given,

g(x) = x^2 - 2

Replace x with -x

g(-x) = (-x)^2 - 2\\\\g(-x) = x^2 - 2

Therefore,

g(x) = g(-x)

Thus the function g(x) is even

4 0
3 years ago
Can someone solve this?
aleksley [76]

Answer:

Considering the Law of Cosines:

c^2=a^2+b^2-2ab*cosC

a=14mi; b=24mi; c=CA; C=91degrees

\cos \left(91^{\circ \:}\right)=-0.01745\dots

c^2=14^2+24^2-2(14)(24)*\cos \left(91^{\circ \:}\right)\\c^2=196+576-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*(-0.01745)\\c^2=772+11.7264\\c=\sqrt{772+11.7264} \\c=\sqrt{783.7264}\\c=27.99mi

4 0
3 years ago
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