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Ivenika [448]
3 years ago
15

The grades on a language midterm at Loyola are roughly symmetric with u = 69 and 0 = 4.0.

Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0

Answer:

Step-by-step explanation:

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$30 each. Unless that's not the answer you are looking for.
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Can someone please help me this is due soon​
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In Mr. Diaz’s class, 20% of the students received a grade of “A” on their report cards. There are 25 students in
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Find the angles between -pi and pi that satisfy:<br><br> (−√3) sin(v)+cos(v)=√3
MAXImum [283]

Observe that

\sin\left(\dfrac\pi6-v\right)=\sin\dfrac\pi6\cos v-\cos\dfrac\pi6\sin v=\dfrac12\cos v-\dfrac{\sqrt3}2\sin v

In the original equation, divide both sides by \dfrac12:

-\sqrt3\sin v+\cos v=\sqrt3\implies\dfrac12\cos v-\dfrac{\sqrt3}2\sin v=\dfrac{\sqrt3}2

\implies\sin\left(\dfrac\pi6-v\right)=\dfrac{\sqrt3}2

Next,

\sin x=\dfrac{\sqrt3}2\implies x=\dfrac\pi3+2n\pi,x=\dfrac{2\pi}3+2n\pi

where n is any integer. Then

\sin\left(\dfrac\pi6-v\right)\implies v=-\dfrac\pi6-2n\pi,v=-\dfrac\pi2-2n\pi

Fix n=0 to ensure -\pi, so that

v=-\dfrac\pi6,v=-\dfrac\pi2

3 0
3 years ago
The distance between the points (-1, -6) and (-19, -6) is units
Vladimir [108]

Answer:

18

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\sqrt{  {( - 9 -  - 1)}^{2} +  {( - 6 -  - 6)}^{2} }

\sqrt{ {( - 18)}^{2} }

\sqrt{324}

3 0
2 years ago
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