1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
crimeas [40]
3 years ago
10

FIND THE PRODUCT [5 5] [-4 9] [-2 3] [8 7 ]

Mathematics
1 answer:
Llana [10]3 years ago
6 0

Answer:

Step-by-step explanation:

لنقود بميراث قنسمضمثهفت فقهقعثنقتلعز فنثيهبتدرقنثهيهلنقنلنث بنيوي فني لر

You might be interested in
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7Dx%20-%205%20%20%2B%20171%20%3D%20x" id="TexFormula1" title=" \frac{1}{
Butoxors [25]

Answer:

x=249

Step-by-step explanation:

1/3x-5+171=x

1/3x+166=x

166=x-1/3x

166=2/3x

x=166/(2/3)

x=(166/1)(3/2)

x=498/2

x=249

7 0
3 years ago
Write 38.5% as a decimal
Brrunno [24]
0.385 there you go your welcome
7 0
3 years ago
A company has two large computers. The slower computer can send all the company's email in minutes. The faster computer can comp
postnew [5]

Both the computers will take 18 minutes to do the job together.

The slower computer sends all the company's email in 45 minutes.

The faster computer completes the same job in 30 minutes.

Let's take minutes t  to complete the task together.

As they complete one job, we get the following equation:

\frac{t}{45}+\frac{t}{30}=1

LCM of 45 and 30 is:

45 = 3 x 3 x 5

30 = 2 x 3 x 5

LCM = 2 x 3 x 3 x 5 = 90

Now, solving for t;

⇒\frac{2t+3t}{90} = 1\\\frac{5t}{90} =1\\5t=90\\

Dividing both sides by 5;

\frac{5t}{5}=\frac{90}{5}

We get t = 18

Hence, it will take both the computers 18 minutes to do the job together.

A company has two large computers. The slower computer can send all the company's emails in 45 minutes. The faster computer can complete the same job in 30 minutes. If both computers are working together, how long will it take them to do the job?

Learn more about work and time here brainly.com/question/13086625

#SPJ4

6 0
2 years ago
14 boys and 21 girls will be equally divided into groups find the greatest number of groups that can be creative no one is left
solmaris [256]
14 boys and 21 girls

u can make 7 groups....each containing 2 boys and 3 girls
7 0
4 years ago
Help on math! First correct answer will get brainliest answer
pshichka [43]

Let's look at the terms of the sequence for different values of n, starting from 0.

a₀ = 0/1 = 0

a₁ = 1/(1 +1) = 1/2

a₂ = 2/(2 + 1) = 2/3

a₃ = 3/(3 + 1) = 3/4

a₄ = 4/5

a₅ = 5/6

a₆ = 6/7

a₇ = 7/8

a₈ = 8/9

a₉ = 9/(9+1) = 9/10

a₁₀ = 10/(10+1) = 10/11 and so on

Let's look at the terms. As n gets bigger the terms gets closer to 1. We started with 0, then to one half, then two thirds, and as we get larger and larger, the terms are getting closer to 1. Let's choose a really big n and see.

a₉₉₉ = 999/(999 + 1) = 999/1000

Or an even bigger n:

a₉₉₉₉₉₉₉₉₉ = 999999999/(999999999 + 1) = 999999999/1000000000ⁿ

So as n gets really really large - and close to infinity - the terms get closer to 1.

7 0
4 years ago
Other questions:
  • Hans made $187 for 11 hours of work.
    14·2 answers
  • A livestock pen is built in the shape of a rectangle that is twice as long as it is wide. The perimeter is 48 feet. If the mater
    12·1 answer
  • What is the value of x?<br><br> Enter your answer in the box.<br><br> X=
    14·1 answer
  • HELPPP!!<br> x - $445.42 = $101.53
    5·2 answers
  • Ade has two similar scale models of the same pyramid. The first model has a
    12·1 answer
  • Calculate the length of AC to one decimal?
    7·1 answer
  • Write log[8]y=x as an exponential function. Please show work!
    14·1 answer
  • Find the values of the sine, cosine, and tangent for angle A
    12·1 answer
  • There are 234 pieces of candy in 9 bags of candy. If there are the same amount of pieces of candy in each bag, how many total pi
    13·1 answer
  • HELP ASAP GVING BRAINLESIT
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!