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3 years ago

Complete the comparison : 27> ?

Mathematics

1 answer:

rjkz [21]3 years ago

5 0

Is there more to the problem?

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Gemma had 25.75 grams of frosting to make a cake. She decided to use only 15.5 grams of the frosting. How much frosting does Gem

Finger [1]

Answer:

10.2 grams

Step-by-step explanation:

Gemma had 25.75 grams of frosting

Used 15.5 grams

25.75 - 15.5 = 10.2 grams

8 0

3 years ago

Tell whether the sequence is arithmetic. If it is, identify the common difference.

kiruha [24]

Answer:

Option A is correct not arithmetic

Explanation:

We have given terms $\frac{1}{2},{1}{3},{1}{4}$ these terms are not an arithmetic progression because

Arithmetic progression is the sequence of terms in which difference between successive and proceeding terms is same.

$d=a_2-a_1$

we can see the difference between $\frac{1}{3}$ and $\frac{1}{2}$ is $\frac{-1}{6}$

Whereas, the difference between $\frac{1}{4}$ and $\frac{1}{3}$ is $\frac{-1}{12}$ .

5 0

3 years ago

Read 2 more answers

∠ABD is formed by a tangent and a secant intersecting outside of a circle. If minor arc AC = 78° and minor arc CD = 124°, what i

lana [24]

Minor arc AD is 360° -124° -78° = 158°. Then angle ABD is
(158° -78°)/2 = 40°

The appropriate selection is
C) 40°

4 0

3 years ago

Read 2 more answers

Which reason justifies step 2 in the proof

faust18 [17]

Answer:

Step-by-step explanation:

Given: ∠N≅∠S, line l bisects TR at Q.

To prove: ΔNQT≅ΔSQR

Proof:

From ΔNQT and ΔSQR

It is given that:

∠N≅∠S (Given)

∠NQT≅∠SQR(Vertical opposite angles)

and TQ≅QR ( Definition of segment bisector)

Thus, by AAS rule,

ΔNQT≅ΔSQR

Hence proved.

Statement Reason

1. ∠N≅∠S given

2. ∠NQT≅∠SQR Vertical angles are congruent

3. line l bisects TR at Q. given

4. TQ≅QR Definition of segment bisector

5. ΔNQT≅ΔSQR AAS theorem

Hence proved.

Thus, option D is correct.

3 0

3 years ago

From past experience, the organization knows that about 20% of all potential donors will agree to give something if contacted by

Veronika [31]

Answer:

Total number of donor who will give first $ 100 = 100 people

Step-by-step explanation:

Given that:

Total percentage of people who donate when contact by phone 20%

Percentage of donating people who will give $100 or more = 5% = 0.05

Total number of donor who will give first $ 100 can be calculated as

calculate the percentage of donor who will give first $ 100

$P(X) = 0.05\times 0.20 = 0.01\ percent$

$\mu_x = \frac{1}{0.01}$

so, total number of the donor who will give first $ 100 = 100 people

3 0

3 years ago