Give the equation of the circle centered at the origin and
passing through the point (4,0)
1 answer:
Answer:
x² + y² = 4²
Step-by-step explanation:
The standard equation of a circle centered at the origin and with radius r is
x² + y² = r²
Note that the point (4, 0) is 4 units horizontally and to the right of the center (0, 0). Thus, we know immediately that the radius is 4.
Thus the equation of this circle is x² + y² = 4²
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