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SVEN [57.7K]
3 years ago
13

Give the equation of the circle centered at the origin and passing through the point (4,0)

Mathematics
1 answer:
zimovet [89]3 years ago
4 0

Answer:

x² + y² = 4²

Step-by-step explanation:

The standard equation of a circle centered at the origin and with radius r is

x² + y² = r²

Note that the point (4, 0) is 4 units horizontally and to the right of the center (0, 0).  Thus, we know immediately that the radius is 4.

Thus the equation of this circle is x² + y² = 4²

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If 6 is added to three quarters of a certain number, the result is 42 . Find the original number​
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Answer:

Step-by-step explanation

Hello!

3x/4 + 6=42

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x= 144/3 =48

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Find the center and radius of the circle.<br> (x + 3)2 + (y + 4)2 =9
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