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Nataly [62]
3 years ago
6

PLEASE HELP PICTRE SHOWN

Mathematics
1 answer:
matrenka [14]3 years ago
8 0
First, you add 1 to both sides. Then square both sides to get rid of the square root. After that you just solve it like a normal equation when you are left with 4x-2=9.
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Nevermind. I dont need anything
AlladinOne [14]
Answer: ok
Explanation: doesn’t need anything
5 0
3 years ago
a farmer is splitting 23 pounds of oats into 9 separate bins for his horses how many pounds of oats will be in each bin
lilavasa [31]
To solve this problem, we must first divide 23/9, which is already in itself an answer. Then, to express it as a mixed fraction you just need to find out how many times 9 can go into 23.

9 x 1 = 9
9 x 2 = 18
9 x 3 = 27

So, the most times 9 can go into 23 is 2 times. 

That give us 2 pounds with a remainder of 5.

So, our mixed fraction is 2\frac{5}{9}

8 0
3 years ago
carol had a birthday party at a local pizza restaurant the bill came 54.80 not including tip to be 15% how much whould that add
luda_lava [24]
It would be 63.02
I hope this helps :)
5 0
3 years ago
Please help me!!!
tester [92]
Hello there!

A) What percent of adults drink only coffee?

Percent of only coffee = 55 - (15 - 5) - (25 - 5) - 5
                                = 55 - 10 - 20 - 5
                                = 20%
Thus, 20% of the adults drink coffee


B) What percent of adults drink only soda?

Percentage of only soda = 45 - (25 - 5) - 5
                                    = 45 - 20 - 5
                                    = 25 - 5
                                    = 20%
Thus, 20% of adults drink only soda

C) What percentage of adults drink none of the beverage types?

Percentage of the beverage types = 100 - 20 - 20 - 5 - 10 - 20 - 5
                                                 = 20%
Thus, 20% percentage of adults drink none of the beverage types.

I hope this answer helps!

As always, I'm here to help!
6 0
4 years ago
An analogue sensor signal is sampled every 0.4ms to convert it into a digital representation. What is the corresponding sampling
kondaur [170]
<h2>Hello! It will be a pleasure to help you! </h2><h2>So let's get started:</h2><h3 /><h2>PART 1. </h2><h3>An analogue sensor signal is sampled every 0.4ms to convert it into a digital representation. What is the corresponding sampling rate?</h3>

Sampling is simply a reduction of a continuous time signal to a discrete time signal. Here we know that an analogue sensor is sampled every 0.4ms to convert it into a digital representation. So sampling rate, also called the sampling frequency or f_{s}, is the average number of samples obtained in one second, that is, samples per second:

f_{s}=\frac{1}{T}

Since we know:

T=0.4ms

Then, the sampling rate is:

f_{s}=\frac{1}{0.4ms} \\ \\ f_{s}=2,500 \ samples \ per \ second \\ \\ Or: \\ \\ \boxed{f_{s}=2.5kS/s}

<h3 /><h2>PART 2. </h2><h3>According to the Sampling Theorem, for this sampling rate value, what will be the highest frequency in the digital representation, assuming the lowest frequency in the sensor signal is very close to zero.</h3><h3 />

Sampling Theorem (Nyquist Theorem) States:

<em>A </em><em>continuous time signal </em><em>can be completely represented in its samples and recovered back, if the sampling frequency </em>f_{s} <em>is greater than or equal to twice frequency component of the message signal.</em>

In other words:

f_{s}\geq 2f_{m}

So, the highest frequency in the digital representation will be:

f_{m}=\frac{2500}{2} \\ \\ \boxed{f_{m}=1.25kHz}

<h2>PART 3. </h2><h3>If each sample is quantised into 2048 levels, what will be the resulting bit-rate, giving your answer in scientific notation to 2 decimal places?</h3>

Everything is Ok up to this point! But let me explain something. We do all these things in order to get a faithful reproduction of the digital signal. So the Analog-to-Digital Conversion (ADC) allows us to do that.

In this final part, each sample is quantised to 2048 levels, so this number can be written as:

2048=2^{11}

That is, there are (2^{11}) \ levels, in other words, it takes:

11 \ bits \ per \ sample

Finally, the resulting bit-rate is:

11 \times 2500 \\ \\ =27500 \ bits \ per \ second

In scientific notation to two decimal places:

\boxed{2.75 \times 10^4 \ bits \ per \ second}

8 0
3 years ago
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