Answer: A. 0.0164
Step-by-step explanation:
Given : The lengths of human pregnancies are normally distributed with a mean 
Standard deviation : 
Let X be the random variable that represents the length of pregnancy of a randomly selected human .
z-score : 
For X = 300
Now, the probability that a pregnancy last at least 300 days will be :-
Hence, the probability that a pregnancy last at least 300 days =0.0164
Answer:
-6a-48
Step-by-step explanation:
distubutive property
80 because 16 divided by 20%
of means multiply but in this case divide
To get 4% of 800 you times 800 by 4 and divide it by 100. Once you have that amount you add it to 800 to find the amount you will have in your bank the first year.
To get the next year's amount you then get 4% of 832(because after the first year you have more than $800) and then add the 4% to 832, that is the answer for the second year.
To find the third year's amount you get 4% of the new amount (last year's total) and add it to last year's total, that is your total for the third year.
So the first year will be:
(800x4÷100)+800
=32+800
=832
The second year will be:
832+(832x4÷100)
=832+33.28
=865.28
The third year will be:
(865.28×4÷100)+865.28
=34.61(rounded off)+865.28
=899.89
